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Its very Simple that using Enumerated data type you are making special integers that flow within range, While a typedef is redefining data type with new name. Example: like defining enum Days{sun,mon,tue.....} makes an integer definition that can have 0-7 values So if u do following: Days x=sun; or Days x=0; then x=x+2; is 2 or tue and x=x+7; is 0 or sun again... Means its modulo 7 data type ................. While doing this: typedef Days WeekDays; renames Days as WeekDays Similary typedef int NUMBER; renames int as NUMBER .But wait it is one more name for the data type.. So simply enum creates a numeral modular datatype with a range while typedef creates another name for it. Rupesh K Joshi

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βˆ™ 2005-09-29 12:49:49
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Q: What is the difference between enumrerated datatype and typedef?
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What is the difference between a macro and typedef?

A Macro is a preprocessor directive means that before compilation the macros are replaced. Where as typedef is defining a new data type which is same as the existing data type. Syntax: typedef Existing datatype New datatype For example typedef int NUMBER; Here NUMBER (New datatype)is defined as a data type which contains the properties same as int(Existing datatype). You can declare a variable of int as NUMBER a; is same as int a; similarly typedef int* NUMBERPOINTER; NUMBERPOINTER a; Here a is a pointer of integer type.


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A typedef is a compiler macro. A reference is a pointer, usually implemented with transparent syntax. They have no relationship between each other.


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#define is a preprocessor directive used to declare macros. typedef is a C++ keyword to define a data type.


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A typedef is a type definition.


Difference between define and typedef?

typedef keep the property of attributes whereas #define won't for example #define char* m_type typedef char* p_type m_type a, b; p_type c,d In above case a, c and d are pointer types , where as b in char type only. Which is not our intention. In another example which shows #define keeps string attributes whereas typedef won't. #define int INT; typedef int MYINT unsigned MYINT a; unsigned INT a; The above example won't work as it won't change to unsigned int a. And in #define case it will simply works!!!.


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