An alpha particle consists of 2 Neutrons and 2 Protons, therefore A=4, Z=2.
For Ra-224: A=224, Z=88.
Subtracting the values for the alpha particle from Radium-224:
A = (224-4) = 220
Z = (88-2) = 86
The nucleus with a Z of 86 is Radon, or in this case, Rn-220.
So that: Ra-224 --> Rn-220 + Alpha
But alpha particles are just Helium-4 nuclei.
Ra-224 --> Rn-220 + He-4
224
224
In alpha decay, the nucleus emits an alpha particle (helium nucleus) consisting of 2 protons and 2 neutrons. Thallium-230 undergoes alpha decay to produce an alpha particle (helium-4 nucleus) and become lead-226. The balanced nuclear equation for this process is: ([^{230}{81}Tl \rightarrow ^{4}{2}He + ^{226}_{82}Pb]).
The equation for alpha decay of thorium-228 is 228Th -> 224Ra + 4He, where thorium-228 decays into radium-224 by emitting an alpha particle (helium nucleus). The equation for beta decay of aluminum-28 is 28Al -> 28Si + e + v, where aluminum-28 decays into silicon-28 by emitting a beta particle (electron) and an antineutrino.
The equation for the alpha decay of plutonium-244 is: [ ^{244}{94}Pu \rightarrow ^{240}{92}U + ^4_2He ]
Alpha emission means that an alpha particle (2 protons + 2 neutrons) are emitted, so the original nucleus has 2 protons and 2 neutrons more.
Radium undergoes radioactive decay, specifically alpha decay, to become radon. Radium-226 (226Ra) will undergo alpha decay releasing that alpha particle, which is a helium-4 nucleus, to become radon-222 (222Rn).
Go nnn and the other one and get it.
Since an alpha particle has 2 protons and 2 neutrons, you have to add 4 to the atomic mass. You also have to add 2 to the atomic number. That is, look up the number for protactinium in a periodic table, and add two to that number.
The radioactive gas with 136 neutrons is Radon-220, also known as thoron. It is a naturally occurring radioactive gas that is part of the decay chain of uranium-232. Thoron is produced by the decay of radium-224 and has a half-life of about 55 seconds.
224 rn 86
14*16 = 224