When radium-226 undergoes alpha decay, it becomes radon-222. We write the equation like this: 88226Ra => 24He + 86222Rn Here we see the alpha particle written as a helium-4 nucleus, which is, in point of fact, what it is. Notice that the numbers that are subscripted are equal on both sides of the equation, and the superscripted numbers are as well. They must balance for your equation to be correct.
Polonium 210-----------alpha particles-----------Lead 206
Polonium 209-----------alpha particles-----------Lead 205
Polonium 208-----------alpha particles-----------Lead 204
For other isotopes see the list at: http://en.wikipedia.org/wiki/Polonium#Isotopes
First you must decide what isotope of platinum you are talking about. Most elements have several isotopes. Once you decide that, just subtract 2 protons from the number of protons, and 2 neutrons from the number of neutrons, to get the daughter product - since an alpha particle consists of 2 protons and 2 neutrons.
The equation for the alpha decay of 213At is:85213At --> 83209Bi + 24He
representing the alpha particle as a helium nucleus.
Only one isotope of platinum can undergo alpha decay: platinum-190.
platinum-190 decays to osmium-186 which is stable
Here is an error: polonium 24 doesn't exist.
85At217 -----> 2He4 + 83Bi213
229Th-------alpha particle-----------225Ra
The equation for the alpha decay of 233Pu:94233Pu --> 92229U + 24He2+where the alpha particle is represented as a helium nucleus.Note that 233Pu decays by alpha decay with a probability of only 0.12%. The other 99.88% is Beta+ decay.
The equation for the alpha decay of radon-222 takes the following form. Radon-222 ----> He + Polonium. In an alpha decay, the atom loses 2 neutrons and 2 protons.
Lead-210 decays by alpha or beta decay. The equation for the alpha decay of 210Pb is: 82210Pb --> 80206Hg + 24He representing the alpha particle as a helium nucleus. The equation for the beta decay of 210Pb is: 82210Pb --> 83210Bi + -10e where the -10e is an electron.
Mercury-201 is stable and does not decay.
224
229Th-------alpha particle-----------225Ra
Th-230(alpha)Ra-226.
Po-216- -----------------> Pb-212
alpha
alpha
The equation for the alpha decay of 226Ra: 88226Ra --> 86222Rn + 24He The alpha particle is represented as a helium (He) nucleus.
Plutonium-241 decays by both beta- and alpha decay. For beta- decay the equation is ...94241Pu -> 95241Am + e- + v-eNot asked but answered for completeness sake, for alpha decay the equation is ...94241Pu -> 92237U +24He2+
The equation for the alpha decay of 233Pu:94233Pu --> 92229U + 24He2+where the alpha particle is represented as a helium nucleus.Note that 233Pu decays by alpha decay with a probability of only 0.12%. The other 99.88% is Beta+ decay.
The equation for the alpha decay of radon-222 takes the following form. Radon-222 ----> He + Polonium. In an alpha decay, the atom loses 2 neutrons and 2 protons.
If radon-210 undergoes alpha decay, it will produce the alpha particle (which is a helium-4 nucleus) and polonium-206. The equation looks like this: 86210Ra => 24He + 84206Po You'll note that in the balanced nuclear equation, the atomic numbers, which are the subscripts, balance on both sides of the equation (86 = 2 + 84). The atomic masses, which are the superscripts, also balance on both sides of the equation (210 = 4 + 206).
Lead-210 decays by alpha or beta decay. The equation for the alpha decay of 210Pb is: 82210Pb --> 80206Hg + 24He representing the alpha particle as a helium nucleus. The equation for the beta decay of 210Pb is: 82210Pb --> 83210Bi + -10e where the -10e is an electron.