KBr + I2(aq) --> KBr + I2(aq)
It does not react because bromine is more electronegative and reactive than iodine.
Bromine and Potassium iodide react to form Potassium bromide and Iodine.
2KI + Cl2 = 2KCl + I2
Its actually: 2KI(aq)+Br2(aq)-> I2(s)+2KBr(aq)
Br2 (g) + 2 KI (aq) 2KBr (aq) + I2 (s)
because it is gay
The word equation for potassium bromide and iodine water is: potassium bromide + iodine water -> potassium iodide + bromine.
Bromine and Potassium iodide react to form Potassium bromide and Iodine.
2KI + Cl2 = 2KCl + I2
The word equation for the reaction between potassium and iodine is: potassium + iodine → potassium iodide.
Its actually: 2KI(aq)+Br2(aq)-> I2(s)+2KBr(aq)
The stability of molecules is influenced by the strength of the chemical bonds present. Potassium bromide forms strong ionic bonds between potassium and bromine atoms, leading to stability. Iodine bromide forms weaker covalent bonds between iodine and bromine atoms, making it less stable.
Br2 (g) + 2 KI (aq) 2KBr (aq) + I2 (s)
Iodine is not reactive with potassium chloride in an aqueous solution because iodine is less reactive than chlorine. Chlorine is more likely to react with potassium to form potassium chloride, leaving the iodine unreacted.
because it is gay
Iodine is less reactive than bromine, so it is not able to displace bromide from potassium bromide in a single displacement reaction. The reactivity of halogens decreases as you move down the group in the periodic table, with fluorine being the most reactive and iodine being the least reactive.
Yes, it is correct.
No. However, bromine would displace iodine in potassium iodide.