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What is the hexadecimal equivalent of the Ethernet address of 01011010 00010001 01010101 00011000 10101010 00001111?
Wiki User
∙ 15y ago
5A 11 55 18 AA 0F
Wiki User
∙ 15y ago
Anonymous
a
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How many bit strings of length 8 begin with three 0s?
There are 32... 00000000 00000001 00000010 00000011 00000100 00000101 00000110 00000111 00001000 00001001 00001010 00001011 00001100 00001101 00001110 00001111 00010000 00010001 00010010 00010011 00010100 00010101 00010110 00010111 00011000 00011001 00011010 00011011 00011100 00011101 00011110 00011111 The most significant three bits in an octet (a byte) are required to be 0 (zero). No further requirement is made about the state of the remaining 5 bits; the bit pattern in the byte thus is 000x xxxx (where 'x' can be either '0' or '1'). Five bits of 'x' allow for 25 = 32 combinations.
What is the hexadecimal equivalent of the ethernet address 010111010 00010001 01010101 00011000 10101010 00001111?
This should be an invalid MAC address because the first octet is 9 bytes long. However it converts out to BA:11:55:18:AA:F. However this is not a real MAC address since the OUI (first three octets are not registered to any corporation.) Here are the results of your search through the public section of the IEEE Standards OUI database report for BA:11:55: Sorry! The public OUI listing contains no match for the query BA:11:55If you want to know the math behind it it becomes tricky. Hex is a 16 base system. We're used to a 10 base system 0-9. Hex runs 0-16 so it counts like this0=01=12=23=34=45=56=67=78=89=9A=10B=11C=12D=13E=14F=15 So to count by Hex 0F would =15Then 10 would = 16. You cannot look at it like a ten, it is a one, zero. that's one group of 16 and 0 ones. So 20 (two zero) would equal 32 (two sixteens)With the basics of hex we can convert the binary to decimal.To count by binary we once again have to thing a bit differently. while they look like a bunch of ones and zeros they each stand for a different number with each place multiplying the previous number by 2. So it counts 1,2,4,8,16,32,64,128. Only it is read right to left 128,64,32,16,8,4,2,1 The binary number 10101010 can be calculated like this 128 64 32 16 8 4 2 11 0 1 0 1 0 1 0 So that is one of each 128,32,8,2128+32+8+2=170 to convert this 170 to hex we can devide it by 16 170/16=10.625That gives us 10 full groups of 16 which is a Hexidecimal (A) or 160. This leaves us with a remainder of 10, which we know is another (A). So the Hex for 10101010 = AA
How many 8 digit palindromic numbers are there?
a 8-digits palindromic number is a number consisting of a 4-digits number written and then written backward, i.e. 1234 4321 so there are as many palindromic 8-digits numbers as 4-digits numbers so from 1000 to 9999, so there are 8999 palindromic 8 digits number (I assumed that 00011000 is not to be considered as a valid 8 digit number)
