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0.512 degrees Celsius/mol
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∙ 13y ago
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What is the accepted Ka value for sodium hydroxide?
NaOH does not have a Ka because it is not an acid. Ka is the concentration of the acid, therefore non valid. It can have a Kb though. Hope this helps
What is the normal pH for H2O and What happens if H2O's pH is abnormal?
The pH of water [H2O] is generally 7, and hence neutral. If the pH of a body of water is above or below the previously established value of 7, it could mean a large number of things, generally outside the realms of the empircal formula, i.e. a foreign substance.
What is the full form of h2o?
h2o
H2o is the formula for what compound?
The formula is H2O. The name of this compound is water.
What do you get from AgNO3 H2O?
AgNO3 + H2O ---> HNO3 + AgOH
What is KB for cn- aq h2o l hcn aq oh-aq?
Kb=[HCn][OH-] [CN-]
What is Kb for C5H5N(aq) H2O(l) C5H5NH (aq) OH-(aq)?
kb=[C5H5NH+][OH-]/[C5H5N]
What is Kb for CH3NH2(aq) H2O(l) CH3NH3 (aq) OH-(aq)?
Kb = [CH3NH3 +] [OH-] / [CH3NH2]
What is KB for c5h5n aq h2o l c5h5nh aq oh- aq?
kb=[C5H5NH+][OH-]______[C5H5N]
What is KB for cn aq h2o l hcn aq oh aq?
Kb=[HCN][OH-]/[CN-]
What is KB for c5h5n aq h2o l c5h5nh aq oh aq?
Kb=c5h5nh+oh- / c5h5n (apex.)
What is the KB expression for aniline?
The KB expression for aniline c6h5nh2 is: For C6H5NH2 + H2O >< C6H5NH3+ + OH-Kb = 4.3 x (10 ^ -10) = [C6H5NH3+][OH-] / [C6H5NH2]
What is Kb for CH3NH2(aq) plus H2O(I) CH3NH3 plus (aq) plus OH-(aq)?
Kb = [CH3NH3 +] [OH-] / [CH3NH2]
What is the KB expression for aniline c6h5nh2?
The KB expression for aniline c6h5nh2 is: For C6H5NH2 + H2O >< C6H5NH3+ + OH-Kb = 4.3 x (10 ^ -10) = [C6H5NH3+][OH-] / [C6H5NH2]
Prove that Kw equals product of Ka and Kb for an acid-base pair in water?
dissociation of acid in water: A + H2O <-> A- + H3O+ with dissociation constant Ka = [A-][H3O+]/[A][H2O] = [A-][H3O+]/[A]. dissociation of base in water: B + H2O <-> HB+ + OH- with dissociation constant Kb = [HB+][OH-]/[B][H2O] = [HB+][OH-]/[B] dissociation of water in itself: 2H2O <-> H3O+ + OH- with dissociation constant Kw = [H3O+][OH-]/[H2O]^2 = [H3O+][OH-] where [H2O] has been ommitted because it is a pure liquid. substituting relations for Ka and Kb into Kw gives: Kw = [H3O+][OH-] = (Ka[A]/[A-])(Kb[B]/[HB+]) = KaKb where [A] = [HB+] and [B] = [A-].
What Kb value represents the weakest base?
Kb = 3.8 10-10
What is Kb for (CH3)3N(aq) H2O(l) (CH3)3NH (aq) OH-(aq)?
Kb=[(Ch3)3 NH+][OH-]/[(Ch3)3 N]
