0.512 degrees Celsius/mol
:)
The accepted Ka value for sodium hydroxide (NaOH) is not applicable, as NaOH is a strong base and completely dissociates in water. Instead, the equilibrium constant Kb (base dissociation constant) is typically used for strong bases. The Kb value for NaOH is approximately 1 x 10^-15.
To find the pOH from the given pH value (pH = 11.32), subtract the pH from 14 (pH + pOH = 14) to get pOH. Then use the pOH to find the hydroxide ion concentration in the solution. Finally, use the hydroxide ion concentration along with the initial concentration of hypoiodite ion to determine the KB value for the hypoiodite ion using the expression for the KB of a weak base.
To find the molarity of ammonia solution, first calculate the concentration of OH- ions in the solution using the pH value. From there, use the Kb value to find the concentration of NH3. Finally, convert the concentration of NH3 to molarity to get the answer.
The choice between the H2O crystal necklace and the H2O locket ultimately depends on personal preference. The crystal necklace may be more versatile in terms of styling, while the locket can hold sentimental value as it can encase a small item or photo. Choose based on which design resonates more with you or the intended wearer.
To find the boiling point elevation of the solution, you can use the formula: ΔTb = i * Kb * m, where i is the van't Hoff factor, Kb is the ebullioscopic constant, and m is the molality of the solution. Plug in the values given and solve for ΔTb. Then, add this value to the boiling point of the solvent (100.0°C) to find the boiling point of the solution.
The Kb value for CH3NH2(aq) is 4.4 x 10^-4.
kb=[C5H5NH+][OH-]______[C5H5N]
The KB expression for aniline c6h5nh2 is: For C6H5NH2 + H2O >< C6H5NH3+ + OH-Kb = 4.3 x (10 ^ -10) = [C6H5NH3+][OH-] / [C6H5NH2]
The KB expression for aniline c6h5nh2 is: For C6H5NH2 + H2O >< C6H5NH3+ + OH-Kb = 4.3 x (10 ^ -10) = [C6H5NH3+][OH-] / [C6H5NH2]
Kb = [CH3NH3 +] [OH-] / [CH3NH2]
The Kb for C5H5N (pyridine) is 1.7 x 10^-9. This value indicates the strength of the base in solution, with lower values suggesting a weaker base and higher values indicating a stronger base.
Kb = 3.8 10-10
Kb=c5h5nh+oh- / c5h5n (apex.)
The pKa value of H2O is approximately 15.7.
The relationship between Ka and Kb values is that they are related by the equation Kw Ka Kb, where Kw is the ion product of water. If you know the Kb value, you can determine the Ka value by rearranging the equation to solve for Ka.
The Kb value for the conjugate base CN- (cyanide ion) is 2.5 x 10^-5.
Kb = 55 It is a very strong base therefore it completely dissociates.