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1 mole S atoms = 32.065 g S (atomic weight in grams)
1 mole S atoms = 6.022 x 1023 atoms S (Avogadro's number)
Convert atoms to moles.
2.01 x 1022 atoms S x (1mol S/6.022 x 1023 atoms S) = 0.0334mol S
Convert moles to mass in grams.
0.334mol S x (32.065g S/1mol S) = 10.7g S
vishesh bansal
Geovanny Nader
Wiki User
∙ 10y ago(2.68 x 10^22 atoms) x (238 g U / 6.022 x 10^23 atoms) = 10.59 g of U.
The number least significant figures in the multiplication and division problem is 3 significant figures (2.68). So, following significant figure rules for multiplication, your answer should have 3 significant figures.
The final answer is: 10.6 g U
Wiki User
∙ 12y ago1 mole S atoms = 32.065 g S (atomic weight in grams)
1 mole S atoms = 6.022 x 1023 atoms S (Avogadro's number)
Convert atoms to moles.
2.01 x 1022 atoms S x (1mol S/6.022 x 1023 atoms S) = 0.0334mol S
Convert moles to mass in grams.
0.334mol S x (32.065g S/1mol S) = 10.7g S
Wiki User
∙ 12y agowhat is the mass in grams of 3.75*10^21 atoms of Li
Wiki User
∙ 13y ago2.60 X 10^22 atoms of Uranium (1 mole U atoms/6.022 X 10^23)(238.0 grams/1 mole U)
= 10.3 grams of Uranium
Wiki User
∙ 13y ago3.93 X 10^22 atoms of uranium (1 mole U/6.022 X 10^23)(238.0 grams/1 mole U)
= 15.5 grams of uranium
Wiki User
∙ 12y agoWiki User
∙ 14y agoFor natural uranium: 238,02891 grams
Wiki User
∙ 11y agoThe gram atomic mass of Uranium is 238.
kai
238.03 g/mol
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How many atoms are in 1.9 g Carbon?
Atomic mass of carbon: 12.0 grams1.90 grams × (6.02 × 1023 atoms) / (12.0 grams) = 9.53 × 1022 atoms C
What is the mass of 3.09X1024 atoms of sulfur in grams?
I think you meant 3.09x10^24 atoms of sulfur. 3.09x10^24 atoms * (1 mol / 6.02x10^32 atoms) * (32 g / 1mol) = 165 grams
What is the molar mass of sulfur molecule?
A sulfur molecule has the formula S8. Multiply the number of sulfur atoms (8) times the atomic weight of sulfur in grams (32.065g). The molar mass of S8 = 256.52g S8.
What has more mass 100 hydrogen atoms 4 sulfur atoms or 1 lanthanum atom?
100 Hydrogen atoms have an atomic mass of 100.794, 4 Sulfur atoms have an atomic mass of 128.26, and 1 Lanthanum atom has an atomic mass of 138.90547.
How many atoms of sulfur are present in 155 g of sulfur?
93,341,000,000,000,000,000,000,000 or 933.41 x 1023 atoms of arsenic. You just take Avogadro's number (6.022 x 1023) and multiply 6.022 by the number of moles (155) and then multiply the product by 1023.
How many atoms of sulfur are in 3.86 g?
For this problem, the atomic mass is required. Take the mass in grams and divide it by the atomic mass. Then multiply it by Avogadro's constant, 6.02 × 1023.3.86 grams S / (32.1 grams) × (6.02 × 1023 atoms) = 7.24 × 1022 atoms
How many atoms of gold are in 5 grams of gold?
Atomic mass of Ag: 107.9 grams5.00 grams × (6.02 × 1023 atoms) / (107.9 grams) = 2.79 × 1022 atoms Ag
How many atoms are in 1.9 g Carbon?
Atomic mass of carbon: 12.0 grams1.90 grams × (6.02 × 1023 atoms) / (12.0 grams) = 9.53 × 1022 atoms C
How many grams do 4.4 x 1022 atoms of potassium weigh. answer in units of grams?
The mass is 2.86 grams but the weight will be 0.028 Newtons.
What is the mass in grams of 3.40x10 22 atoms He?
3.40 X 1022 atoms helium (1 mole He/6.022 X 1023)(4.003 grams/1 mole He) = 0.226 grams ===========
What is the mass of 3.09X1024 atoms of sulfur in grams?
I think you meant 3.09x10^24 atoms of sulfur. 3.09x10^24 atoms * (1 mol / 6.02x10^32 atoms) * (32 g / 1mol) = 165 grams
What is the mass of 5.0g of Fe how many atoms are present?
For this problem, the atomic mass is required. Take the mass in grams and divide it by the atomic mass. Then multiply it by Avogadro's constant, 6.02 × 1023.5.0 grams Fe / (55.9 grams) × (6.02 × 1023 atoms) = 5.38 × 1022 atoms
What is the molar mass of sulfur molecule?
A sulfur molecule has the formula S8. Multiply the number of sulfur atoms (8) times the atomic weight of sulfur in grams (32.065g). The molar mass of S8 = 256.52g S8.
How many atoms are in 37.14 grams of sulfur dioxide?
Sulfur has relative atomic mass of 32 and oxygen have that of 16. The molar mass of sulfur dioxide is 64 grams per mole. Therefore there is approximately 0.58 moles (37.14/64) of sulfur dioxide in given weight.
What is the mass of 4.771E plus 22 atoms of neodymium?
4.771 X 1022 atoms neodymium (1 mole Nd/6.022 X 1023)(144.2 grams/1 mole Nd) = 11.42 grams of neodymium --------------------------------------
How many atoms are present in 3.14g of Cu?
3.14 g Cu = # atomsTake the known mass of copper multiply it by Avogadro number and divided by the atomic weight.Atomic weight of copper:63.5 g3.14 g Cu (6.02 × 1023 atoms) / (63.5 grams) = 2.98 × 1022 atoms of Copper
How many grams of N combine with 7.05x1022 O atoms in N2O5?
The formula N2O5 shows that there are 2/5 as many nitrogen atoms as oxygen atoms in the compound. Therefore, the number of nitrogen atoms required is (2/5)(7.05 X 1022) or 2.82 X 1022 atoms. The gram atomic mass of nitrogen is 14.0067 and, by definition, consists of Avogadro's Number of atoms. Therefore, the mass of nitrogen required to react with the specified amount of oxygen to produce the specified compound is 14.0067 [(2.82 X 1022)/(6.022 X 1023] or 0.656 grams of nitrogen, to the justified number of significant digits.
