In one mole of anything there is an avagadros number amount.
avagadros number = 6.022141523
so in one mole of Na there are 6.022141523 atoms of Na, just as in one mole of uranium there are 6.022141523 atoms of uranium, etc...
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To do this, you need to know the atomic weight of the element you're dealing with, found on any Periodic Table. The atomic weight is the mass in grams of the element in one mole - this will provide you with a conversion factor. So take the measurement in moles and multiply it by the atomic weight to convert to grams. Really what you're doing is dividing the number by 1 mole, and multiplying it by the equivalent of one mole, the atomic weight. That's the thought process behind unit analysis and how you get your "units to cancel".
In this case, the answer is about 34.49 grams Na.
1.50 moles sodium (6.022 X 10^2/1 mole Na)
= 9.03 X 10^23 atoms of sodium
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1.50 moles Na x 22.9 g/mole = 34.4 g (3 significant figures)
The answer is: 9,033.10 23 atoms.
9.33 atoms
16
Vvvv
There are 1.41 e24 atoms of Na in 2.35 mol of NaCl.
1 mole = 6.022 x 1023 4.8mol Na x (6.022 x 1023 atoms Na/mol Na) = 2.9 x 1024 atoms Na
32.7 g x 1 mol/22.99 g = 1.422 mol x 6.022x10^23 molecules/1mol = 8.565 x 10^23 molecules(also called atoms)
the constant Mole (mol): 6.02 x 10^23 are how many atoms you have per mol so the answer can be 7 mol atoms or 6.02 x 10^23 atoms per mol x 7 actual answer is 4.214 X10^24 atoms in 7 mol
you have m = 12.5g M = 107.9g/mol Na = 6.02x10^23atoms/mol = avagadros number N = ? atoms then the number of moles is n = m/M = N/Na gives N = mNa/M = 12.5*6.02x10^23 / 107.9 = 6.97 x 10^22 atoms
1 mole Na = 6.022 x 1023 atoms Na 0.200 mole Na x (6.022 x 1023 atoms/1 mole Na) = 1.20 x 1023 atoms Na
There are 1.41 e24 atoms of Na in 2.35 mol of NaCl.
1 mole = 6.022 x 1023 4.8mol Na x (6.022 x 1023 atoms Na/mol Na) = 2.9 x 1024 atoms Na
1.13x10^23
32.7 g x 1 mol/22.99 g = 1.422 mol x 6.022x10^23 molecules/1mol = 8.565 x 10^23 molecules(also called atoms)
the constant Mole (mol): 6.02 x 10^23 are how many atoms you have per mol so the answer can be 7 mol atoms or 6.02 x 10^23 atoms per mol x 7 actual answer is 4.214 X10^24 atoms in 7 mol
How many atoms of gallium are in 2.85 x 103 g of gallium?
Use this fomula: (m/M)*NA in which m is mass in gram (g), M is molar mass (g/mol) and NA is the Avogadro number (mol^-1)
The definition of one mole is: It is a number (eg. of particles of any kind), like pi is a number (of ratio from diameter to circle).It is a very big number, symbolised as NA (and named after Avogadro):NA = 6.022 * 1023 (-/mol) or (mol-1)So there are 1.62 * NA = 9.76 * 1023 atoms in a mole(it is not important of what kind the atoms are).
2.00 moles sodium (6.022 X 1023/1 mole Na) = 1.20 X 1024 atoms of sodium ---------------------------------------
The amount of moles is also defined as n = N/NA, wheren - amount of molesN - amount of atomsNA - Avogadro constant (approx. 6.02214179×1023 mol-1), thereforeN = n×NA = 0.263×6.02214179×1023 = 1,583823291×1023 atoms.
you have m = 12.5g M = 107.9g/mol Na = 6.02x10^23atoms/mol = avagadros number N = ? atoms then the number of moles is n = m/M = N/Na gives N = mNa/M = 12.5*6.02x10^23 / 107.9 = 6.97 x 10^22 atoms