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Q: What is the mass in grams of 3.011 1023 atoms F?
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What is the mass in grams of 6.022 x 1023 N atoms of mass 14.01 amu?

The molar mass of any element is its atomic weight (amu) in grams, and 1 mol of any element is 6.022 x 1023 atoms. Therefore, the mass in grams of 6.022 x 1023 atoms of N = 14.01g N.


What is the mass in grams of 6.022 x 1023 atoms of 12C?

12


What is the mass of 4.21 x 10 to the 23rd atoms of P?

4.21 × 1023 atoms ÷ (6.02 × 1023 atoms) × 30.97 grams = 21.66 grams P


What is the mass of 8.90 x 1023 lead atoms?

8.90 X 1023 lead atoms (1 mole Pb/6.022 X 1023)(207.2 grams/1 mole Pb) = 306 grams of lead =============


How many atoms are present in 5 grams of AuCl3?

For this problem, the atomic mass is required. Take the mass in grams and divide it by the atomic mass. Then multiply it by Avogadro's constant, 6.02 × 1023. AuCl3= 303.5 grams5.00 grams AuCl3 / (303.5 grams) × (6.02 × 1023 atoms) = 9.92 × 1021 atoms


What is the mass of 1.505 x 10²³ carbon atoms?

To convert atoms to grams, you need to take the number of atoms, divide it by Avogadro's Constant, then multiply it by the atomic mass.Atoms ÷ (6.02 × 1023) × Atomic mass = Mass in grams1.505 × 1023 ÷ (6.02 × 1023) × 12.0 = 3.00 grams Carbon


How many atoms of gold are in 5 grams of gold?

Atomic mass of Ag: 107.9 grams5.00 grams × (6.02 × 1023 atoms) / (107.9 grams) = 2.79 × 1022 atoms Ag


How many aluminum atoms are there in a mass of 16.2 grams?

16. 2 grams aluminum (1 mole Al/26.98 grams)(6.022 X 1023/1 mole Al) = 3.62 X 1023 atoms of aluminum -------------------------------------------


How many atoms are in 1.9 g Carbon?

Atomic mass of carbon: 12.0 grams1.90 grams × (6.02 × 1023 atoms) / (12.0 grams) = 9.53 × 1022 atoms C


What is the mass of 7.8 x 1018 carbon atoms?

3.011 x 1023 atoms of carbon will weigh about 6 grams One mole of carbon atoms weighs 12.011 grams, and there are 6.022 x 1023 atoms in a moles. So you have half as many atoms, so the mass would be half as much or 6.0055 grams to be precise.


How many atoms in 36g of magnesium?

For this problem, the atomic mass is required. Take the mass in grams and divide it by the atomic mass. Then multiply it by Avogadro's constant, 6.02 × 1023.10.6 grams Mg / (24.3 grams) × (6.02 × 1023 atoms) = 2.63 × 1023 atoms


How do you find the mass of a sample of 1.72 x 1023 atoms of potassium?

1 mole K atoms = 39.0983g K (atomic weight in grams)1 mole K atoms = 6.022 x 1023 atoms K (Avogadro's number)Convert known atoms to moles.1.72 x 1023 atoms K x (1mol K/6.022 x 1023 atoms K) = 0.286mol KConvert moles to mass in grams.0.286mol K x (39.0983g K/1mol K) = 11.2g K