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Q: What is the mass in grams of 9.71 x 1024 molecules of methanol?
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What is the mass (in grams) of methanol of 9.09x1024 molecules of methanol?

The mass is 483,62 g.


What is the mass in grams of 9.47 x 1024 molecules of methonal?

The simplest form of the molecular formula for methanol {note corrected spelling} is CH4O, and its gram molecular mass is 32.04. By definition therefore, a mass of Avogadro's Number of molecules contains 32.04 grams. Avogadro's Number is about 6.022 X 1023. Therefore, 9.47 X 1024 molecules of methanol contains [(9.47 X 1024)/(6.022 X 1023)]32.04 or 504 grams, to the justified number of significant digits.


What is the mass(in grams) of 9.401024 molecules of methanol?

The answer is 50,196 g.


What is the mass (in grams) of 9.85x10 to the 24 of methanol (CH3OH)?

9,85x10 to the 24 of methanol (CH3OH) molecules have a mass of 52,405 g.


What is the mass (in grams) of 9.18 1024 molecules of methanol (CH3OH)?

9.18x10^24 molecules CH3OH x 1 mole/6.02x10^23 molecules x 32 g/mole = 488 g (to 3 sig figs)


What is the mass in grams of 9.03 X 1024 molecules of methanol CH3OH?

9.32*1024 (molec's CH3OH) / 6.022*1023 (molec's.mol−1 CH3OH) * 32.04 (g mol−1 CH3OH) = 495.8 g = 496 g CH3OH


What is the mass of 3.62 X 1024 molecules of CH3OH?

192.678 grams CH3OH


What is the mass in grams of 9.32x1024 molecules of methanol CH3OH?

9.32*1024 (molec's CH3OH) / 6.022*1023 (molec's.mol−1 CH3OH) * 32.04 (g mol−1 CH3OH) = 495.8 g = 496 g CH3OH


What is the mass in grams of 9.93x1024 molecules of methanol CH3OH?

I am assuming that the question is: what is the mass, in grams, of 9.93x1024 molecules of methanol (CH3OH). For any question concerning mass and a chemical, we must find the molecular mass by adding the atomic masses from the periodic table: C=12.0g 4H= 4 x 1.01 = 4.04g O=16.0g Total: 32.0g/mole Now, how many moles is 9.93x1024 molecules, if one mole is 6.02x1023? (9.93x1024 ) / (6.02x1023) = 15.5 moles. So, 15.5 moles x 32.0g/mole = 496g.


What is a yottagram?

A yottagram is a unit of mass equal to 1024 grams.


How many molecules are there in 3.46 kg hydrochloric acid?

Mass of HCL given=3.46kgs = 3460 grams of HCL No. of moles of HCL=Mass of HCL provided/Atomic mass of HCL=3460/36.5=94.8 moles no. of molecules=no. of moles x Avogadro number=94.8 x 6.022 x 1023 =57 x 1024 molecules.


How many molecules are in 720 grams of C6H12O6?

The gram molecular mass of C6H12O6 is 180.16, Which can be found from summing 6 times the gram atomic mass of carbon, 12 times the gram atomic mass of hydrogen, and 6 times the gram atomic mass of oxygen. Therefore, by the definition and value of Avogadro's Number, the number of molecules of C6H12O6 in 720 grams of the substance is (720/180.16) X Avogadro's Number, or 2.41 X 1024 molecules, to the justified number of significant digits.