Q: What is the mass in grams of 9.71 x 1024 molecules of methanol?

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The mass is 483,62 g.

9.18x10^24 molecules CH3OH x 1 mole/6.02x10^23 molecules x 32 g/mole = 488 g (to 3 sig figs)

To convert mass to atoms:Find the atomic mass of the element in the substance. You can find atomic masses on the periodic table. Ex. Lithium's atomic mass is 6.9 grams (round if you need to)Then find the mass of the substance in grams. Ex. you have 18.2 grams of a sample of Lithium.The mass of the sample is multiplied by 6.02 * 1023 and divided by the atomic mass.Ex.mass of sample in grams * (6.02 * 1023 atoms) / (atomic mass) = # atoms in grams18.2 grams * (6.02 * 1023 atoms) / (6.9 grams) = 1.59* 1024 atomsThe number 6.02 * 1023 is Avogadro's Constant which is the amount of atoms (or molecules) in one mole.

8.20g of carbon monoxide, how many grams of methanol will be produced?

The mass of 5,2.e10 molecules of fluorine (F2) is 32,809.10e-13 g.

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The mass is 483,62 g.

The simplest form of the molecular formula for methanol {note corrected spelling} is CH4O, and its gram molecular mass is 32.04. By definition therefore, a mass of Avogadro's Number of molecules contains 32.04 grams. Avogadro's Number is about 6.022 X 1023. Therefore, 9.47 X 1024 molecules of methanol contains [(9.47 X 1024)/(6.022 X 1023)]32.04 or 504 grams, to the justified number of significant digits.

The answer is 50,196 g.

9,85x10 to the 24 of methanol (CH3OH) molecules have a mass of 52,405 g.

9.18x10^24 molecules CH3OH x 1 mole/6.02x10^23 molecules x 32 g/mole = 488 g (to 3 sig figs)

9.32*1024 (molec's CH3OH) / 6.022*1023 (molec's.mol−1 CH3OH) * 32.04 (g mol−1 CH3OH) = 495.8 g = 496 g CH3OH

192.678 grams CH3OH

9.32*1024 (molec's CH3OH) / 6.022*1023 (molec's.mol−1 CH3OH) * 32.04 (g mol−1 CH3OH) = 495.8 g = 496 g CH3OH

I am assuming that the question is: what is the mass, in grams, of 9.93x1024 molecules of methanol (CH3OH). For any question concerning mass and a chemical, we must find the molecular mass by adding the atomic masses from the periodic table: C=12.0g 4H= 4 x 1.01 = 4.04g O=16.0g Total: 32.0g/mole Now, how many moles is 9.93x1024 molecules, if one mole is 6.02x1023? (9.93x1024 ) / (6.02x1023) = 15.5 moles. So, 15.5 moles x 32.0g/mole = 496g.

A yottagram is a unit of mass equal to 1024 grams.

Mass of HCL given=3.46kgs = 3460 grams of HCL No. of moles of HCL=Mass of HCL provided/Atomic mass of HCL=3460/36.5=94.8 moles no. of molecules=no. of moles x Avogadro number=94.8 x 6.022 x 1023 =57 x 1024 molecules.

The gram molecular mass of C6H12O6 is 180.16, Which can be found from summing 6 times the gram atomic mass of carbon, 12 times the gram atomic mass of hydrogen, and 6 times the gram atomic mass of oxygen. Therefore, by the definition and value of Avogadro's Number, the number of molecules of C6H12O6 in 720 grams of the substance is (720/180.16) X Avogadro's Number, or 2.41 X 1024 molecules, to the justified number of significant digits.