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What is the mass of 1.89 mol of aspirin?
The answer is 340,49673 g.
How many moles of aspirin (C9H8O4) are in 2.00 g of aspirin?
Aspirin : 180.157 g/mol (according to Wikipedia - props) (0.325g)/(180.157g/mol) = 0.0018mols Unit logic : (g )/ (g/mol) {multiply by reciprocate} = (g) x (mol/g) {"(g/g)= 1} = 1mol = mol
A one gram sample of aspirin contains 75.2 percent by mass of C9H8O4 How many moles of acetylsalicylic acid are in the sample?
There are 0.752 g of acetylsalicylic acid. The FW (formula weight) of aspirin is ~180 g/mol. moles = mass/FW.
What is the mass in grams of 1.40 1021 molecules of aspirin C9H8O4?
0.40 moles of aspirin is 72.1 g.
What is the percent by mass of hydrogen in aspirin?
Molecular Formula = C9H8O4 Mr = 12*9+8+16*4 = 180.160 g/mol %Mass (H) = 8/180.160 * 100 = 4.44%
What is the mass of 0.7891 mol of ferric oxide (Fe2O3)?
Atomic Mass of Fe: 55.8g/mol Atomic mass of O: 16g/mol Molecular mass of Fe2O3: 2(55.8)+3(16) = 159.6g/mol mass = Molecular mass x number of moles mass = 159.6g/mol x 0.7891mol = 125.94g
What is the mass of 0.7891 mol of ferric oxide?
Atomic Mass of Fe: 55.8g/mol Atomic mass of O: 16g/mol Molecular mass of Fe2O3: 2(55.8)+3(16) = 159.6g/mol mass = Molecular mass x number of moles mass = 159.6g/mol x 0.7891mol = 125.94g
What is the mass of 0.7891 mol of ferric oxide Fe2O3?
Atomic mass of Fe: 55.8g/mol Atomic mass of O: 16g/mol Molecular mass of Fe2O3: 2(55.8)+3(16) = 159.6g/mol mass = Molecular mass x number of moles mass = 159.6g/mol x 0.7891mol = 125.94g
What is the molar mass of sodium oxalate?
molar mass is 318 g/mol (2X27)+3(2X12+4X16)=318g/mol
How many grams does 3 moles of CO2 weigh?
Atomic mass of C = 14g/mol Atomic mass of O = 16g/mol Molecular mass of CO2 = 12 + 2(16) = 44g/mol mass = number of moles x molecular mass mass = 3 mol x 44g/mol = 132g
What is the formula mass of CS2?
Formular mass is the sum of the atomic mass' of the corresponding elements. C = 12.011 g/mol S = 32.06 g/mol 12.011 g/mol + 2(32.06 g/mol)= 76.131 g/mol Therefore, the formula mass of CS2 is 76.131 g/mol.
A certain pain reliever was analyzed for aspirin by dissolving 250 mg of the tablet in water and titrating with .0300M KOH Titration required 29.40 mL of base What is percentage by weight of aspirin?
HC9H7O4+KOH--> [C9H7O4]-K+ +H2O moles of KOH= 0.300mol/L x 0.0294L =8.82x10^-4 mol KOH 1 mole of KOH=1 mole of HC9H7O4 moles of HC9H7O4= 8.82x10^-4 mol mass of aspirin= 8.82x10^-4 mol x 180.09 g/mol = 0.15884 g 250mg=0.25g %weight= (weight of solute/weight of sample) x 100% = ( 0.15884g/0.25g) x 100% =63.54% of aspirin
