16 grams per mole. Methane is CH4. Look at the Periodic Table: Carbon is 12 grams/mole and Hydrogen is 1 gram/mole, so 1*12 + 4*1 = 16.
6.022 x 1023 Avagadro's number. 1 mole of anything has this number of molecules.
0.25 moles
First you must find the no. on moles in 1.6g of ch4. ie. ch4=C+h4=12+(1.008x4)=16.032 or 16 approx moles=1.6/16=0.1 No. of electrons=no. atoms ie. no of moles x 6.022x10^23 =0.1x 6.022x10^23 =>6.022 x 10^22(approx)
I think you are asking for the mass of 0.35 moles of methane (CH4). First, we find the molecular mass of methane by addin the masses of all of the atoms. A carbon is 12, and each H is 1, so the molecular mass of CH4 is 16g/mole. Now we multiply 0.35 moles by 16 g/mole. The moles cancel out, and we have 5.6 g.
If you think to 4 moles of methane the number is 24,088563428.10e+23.
Methane reacts with oxygen in the following way. CH4 + 3 O2 --> CO2 + 4 H2O. If 5 moles of oxygen react with 2.8 moles of methane, only 1.67 moles of methane would be consumed because of the molar ratio 1:3. This would produce 1.67 moles of carbon dioxide and 6.67 moles of water.
Taking carbon @ 12.01 g/mol & hydrogen @ 1.01 g/ mol methane has 1 carbon & 4 hydrogen, so it is:12.01g + 4(1.01g) = 16.05g per mole.For 4 moles: 4 x 16.05 g = 64.20 g
First a balanced chemical equation is needed.CH4 + 2O2 -> CO2 + 2H2OThere is a 1:1 ratio of moles between methane and carbon dioxide so the amount of moles of methane used is the exact number of moles of carbon dioxide yielded.To determine the number of moles of methane we take the amount used and divide by methane's mass which is about 16.04 g/mol.100g/ 16.04g/mol=6.234moles of methane.6.234 moles of methane are used and 6.234 moles of carbon dioxide are produced.
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Methane (CH4) has four atoms of hydrogen per molecule. If there are 3 moles of methane, then there are 12 moles of hydrogen.
8.02 / 16.04 = 0.5 moles
When methane undergoes complete combustion, the equation for the reaction is CH4 + 2 O2 -> CO2 + 2 H2O. This shows that the number of moles of carbon dioxide formed are the same as the number of moles of methane reacted, so that 14 moles of carbon dioxide will be formed from 14 moles of methane.
0.25 moles
First you must find the no. on moles in 1.6g of ch4. ie. ch4=C+h4=12+(1.008x4)=16.032 or 16 approx moles=1.6/16=0.1 No. of electrons=no. atoms ie. no of moles x 6.022x10^23 =0.1x 6.022x10^23 =>6.022 x 10^22(approx)
I think you are asking for the mass of 0.35 moles of methane (CH4). First, we find the molecular mass of methane by addin the masses of all of the atoms. A carbon is 12, and each H is 1, so the molecular mass of CH4 is 16g/mole. Now we multiply 0.35 moles by 16 g/mole. The moles cancel out, and we have 5.6 g.
Moles = weight (in g) / molecular weight = 0.289 / 16 = 0.0180 moles.
The formula for methane shows that each molecule of it contains 5 atom: 1 carbon atom and 4 hydrogen atoms. The gram molecular mass of methane is 16.04. Therefore, 28 grams of methane contains 28/16.04 moles of methane and 5 times this number, or 8.7, "moles of atoms", to the justified number of significant digits.
If you think to 4 moles of methane the number is 24,088563428.10e+23.