4.32 moles Barium (6.022 X 10^23/1 mole Ba)
= 2.60 X 10^24 atoms
The molar mass of barium hydride (BaH2) is 137.33 g/mol. Therefore, the mass of 4.80 mol of barium hydride would be 4.80 mol x 137.33 g/mol = 659.184 g.
669 g
The formula mass for barium chloride (BaCl2) can be calculated by adding the atomic masses of each element in the compound. The atomic mass of barium (Ba) is 137.33 g/mol, and the atomic mass of chlorine (Cl) is 35.45 g/mol. Therefore, the formula mass of barium chloride (BaCl2) is 137.33 + (2 * 35.45) = 208.23 g/mol.
The molar mass of barium (Ba) is approximately 137.3 g/mol. So, the mass of 3 moles of barium would be 3 moles x 137.3 g/mol = 411.9 grams.
The molar mass of BaF2 is 175.3238064 g/mol
The molar mass of barium sulfate (BaSO₄) is approximately 233.4 g/mol. You can calculate this by adding the atomic masses of one barium atom, one sulfur atom, and four oxygen atoms.
To convert moles to grams, you need to use the molar mass of barium chloride, which is 208.23 g/mol. Multiply the number of moles (286 moles) by the molar mass to find the grams of barium chloride: 286 moles * 208.23 g/mol = 59,545.78 grams.
The chemical formula for barium hydride is BaH2, which means it is composed of one barium atom and two hydrogen atoms.
The molar mass for anhydrous barium sulfate (BaSO4) is 233.43 g/mol
The chemical formula for Barium Hydride is BaH2. Ba = Barium H = Hydrogen Its molecular mass is 139.34288 g/mol.
Barium fluoride is BaF2. Its empirical formula is BaF2 as well. Hence, its formula mass is same as its molecular mass i.e.175.34g/mol
The molar mass of BaF2 is 175.3238064 g/mol
The molar mass of barium sulfate (BaSO₄) is approximately 233.4 g/mol. You can calculate this by adding the atomic masses of one barium atom, one sulfur atom, and four oxygen atoms.
1 mol Ba X (137.33 g Ba / mol Ba) = 137.33 g Ba2 mol O X (16.00 g O / mol O) = 32.00 g O2 mol H X (1.01 g H / mol H) = 2.02 g HMolar mass of Ba(OH)2 = 171.35 g/mol
Crystallised BaCl2·2H2O will be de-hydrated when heated, loozing 2H2O per mol BaCl2·2H2O
Atomic Mass of Fe: 55.8g/mol Atomic mass of O: 16g/mol Molecular mass of Fe2O3: 2(55.8)+3(16) = 159.6g/mol mass = Molecular mass x number of moles mass = 159.6g/mol x 0.7891mol = 125.94g
Atomic Mass of Fe: 55.8g/mol Atomic mass of O: 16g/mol Molecular mass of Fe2O3: 2(55.8)+3(16) = 159.6g/mol mass = Molecular mass x number of moles mass = 159.6g/mol x 0.7891mol = 125.94g
To find the mass of 0.7891 mol of ferric oxide (Fe2O3), you need to calculate the molar mass of Fe2O3. The molar mass of Fe2O3 is 159.69 g/mol. Multiply the molar mass by the number of moles to find the mass: 0.7891 mol * 159.69 g/mol ≈ 125.94 g. Therefore, the mass of 0.7891 mol of Fe2O3 is approximately 125.94 grams.
Barium is in Group 2, so we know that it makes 2+ ions. If you happen to have a chart of common polyatomic ions, you can find out that phosphate is PO4 and has a 3- charge. So, to even out the charges, we need to get three barium ions and two phosphate ions. Now, the total positive charge (from the barium ions) is 6+, and the total negative charge (from the phosphate ions) is 6-.We see that Ba3(PO4)2 is the chemical formula for barium phosphate.