5mol * 30,973762g/mol = 154,85881g
To find the mass of 5.1 mol of phosphorus (P), you need to know the molar mass of phosphorus. The molar mass of phosphorus is approximately 30.97 grams per mole. Therefore, the mass of 5.1 mol of phosphorus is 5.1 mol x 30.97 g/mol = 157.647 g.
The molar mass of sodium phosphide (Na3P) is calculated by adding the atomic masses of the elements in the compound. The atomic mass of sodium (Na) is 22.99 g/mol, and the atomic mass of phosphorus (P) is 30.97 g/mol. The molar mass of sodium phosphide is therefore 22.99 g/mol + 30.97 g/mol + 30.97 g/mol + 30.97 g/mol = 115.9 g/mol.
The molar mass of p-cresol (4-methylphenol) is approximately 108.14 g/mol.
To convert PO4-P to P2O5, you can use the molar mass of each compound. Phosphorus (P) has a molar mass of 30.97 g/mol, while P2O5 has a molar mass of 141.94 g/mol. So, you can calculate the conversion factor by dividing the molar mass of P2O5 by the molar mass of P to determine how much P2O5 is equivalent to 1 unit of PO4-P.
To calculate the mass of 4.76 moles of Na3PO4, you first need to find the molar mass of Na3PO4. Na has a molar mass of 22.99 g/mol, P has a molar mass of 30.97 g/mol, and O has a molar mass of 16.00 g/mol. The molar mass of Na3PO4 is (322.99) + 30.97 + (416.00) = 163.94 g/mol. Multiply the molar mass by the number of moles: 163.94 g/mol * 4.76 mol = 780.94 grams.
To find the number of moles in 12.0 g of phosphorus, first find the molar mass of phosphorus, which is about 31.0 g/mol. Then, divide the given mass by the molar mass to get the number of moles: 12.0 g / 31.0 g/mol ≈ 0.387 moles.
To solve this, you need to use the mole ratio derived from the chemical formula, P4O10, and you need the molar mass of P. 3.25 mol P4O10 x 4 mol P x 30.97 g P = 403 g P .......................1 mol P4O10 1 mol P
To determine the molar mass for any compound, you multiply the molar mass of each element (atomic mass in grams) times its subscript, which represents the number of atoms of that element. Then add the result for each element. Molar Mass of P4S3 (4 atoms x 30.974g/mol P) + (3 atoms x 32.06g/mol S) = 123.90g/mol P + 96.18g/mol S = 220.08g/mol P4S3
P = 31 mass weight H = 1 mass weight, times that by 3 to get 3 (you do this because you have PH3) Add both mass weights to get 34, then multiply that by the number of mols you have 34 x 3.91 mol = 130 g
Molar mass of MgCl2 is 95gmol-1. So there are 0.566 moles in this mass.
Atomic Mass of Fe: 55.8g/mol Atomic mass of O: 16g/mol Molecular mass of Fe2O3: 2(55.8)+3(16) = 159.6g/mol mass = Molecular mass x number of moles mass = 159.6g/mol x 0.7891mol = 125.94g
Atomic Mass of Fe: 55.8g/mol Atomic mass of O: 16g/mol Molecular mass of Fe2O3: 2(55.8)+3(16) = 159.6g/mol mass = Molecular mass x number of moles mass = 159.6g/mol x 0.7891mol = 125.94g
To find the mass of 0.7891 mol of ferric oxide (Fe2O3), you need to calculate the molar mass of Fe2O3. The molar mass of Fe2O3 is 159.69 g/mol. Multiply the molar mass by the number of moles to find the mass: 0.7891 mol * 159.69 g/mol ≈ 125.94 g. Therefore, the mass of 0.7891 mol of Fe2O3 is approximately 125.94 grams.
molar mass is 318 g/mol (2X27)+3(2X12+4X16)=318g/mol
Atomic mass of C = 14g/mol Atomic mass of O = 16g/mol Molecular mass of CO2 = 12 + 2(16) = 44g/mol mass = number of moles x molecular mass mass = 3 mol x 44g/mol = 132g
Formular mass is the sum of the atomic mass' of the corresponding elements. C = 12.011 g/mol S = 32.06 g/mol 12.011 g/mol + 2(32.06 g/mol)= 76.131 g/mol Therefore, the formula mass of CS2 is 76.131 g/mol.
Molar Mass of Al: 2(27.0g/mol) = 54.0g/mol Molar Mass of O: 3(16.0g/mol) = 48.0g/mol Molar Mass of compound: 102.0g.mol (54.0g/mol / 102.0g/mol) x 100% = 52.9%
Yes, that is what is used. Bromine is I think ~51:49 ratio of Br79 and Br81. Therefore it is somewhere in between (79.9g/mol)