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Q: What is the mass of 7.241023 formula units of barium oxide?
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How many formula units are in 32.6 grams of potassium oxide?

K2O is potassium oxide. Formula mass = 94g32.6 g x 1 FU/94 g = 0.35 formula units


How many formula units in 32.6 grams of potassium oxide?

K2O is potassium oxide. Formula mass = 94g32.6 g x 1 FU/94 g = 0.35 formula units


What is the number of formula units that are in 5.68 moles of magnesium oxide?

5.68 mol MgO x 6.02E23 formula units / 1 mol = 3.42E24 Formula Units


What is the mass of 24.6 formula units of magnesium oxide?

The mass is 991,5 g.


How many formula units are in 0.13 moles of iron (3) oxide?

2.159*10^-25


What is the mass of 9.871023 formula units of aluminum oxide?

Assuming that the number "9.871023" would or should have been written as "9.87 X 1023" if the typographical resources to do so were available to the questioner: Avogadro's Number, which is the number of formula units in a mole of any material, is about 6.022 X 1023. The gram formula mass for aluminum oxide is 101.96. Therefore, the mass of the stated number of formula units of aluminum oxide is: 101.96(9.87/6.022) or about 164 grams, to the justified number of significant digits.


What is the name of the product 2Na2O?

Na2O is sodium oxide. The 2 at the beginning means that there are two formula units of it.


How many formula units of iron (II) oxide are needed to produce 3.6 mol Fe2O3?

7.2


How many oxygen atoms are in one units of the compound Ba(OH)2?

1. The correct chemical formula of barium hydroxide is Ba(OH)2. 2. The molecule of barium hydroxide contain 2 oxygen atoms.


How many total atoms are there in 0.550 mol of barium chloride (BaCl2)?

0.550 mole BaCl2 x 6.02x10^23 formula units/mole x 3 atoms/formula unit = 9.93x10^23 atoms


What is the mass of a barium atom?

The mass of a barium atom is approximately 137 atomic mass units (u).


How many nitrogen atoms are in 18.8 g of barium nitride?

Barium nitride is Ba3N2 (from the rules of ionic bonding). Its molar mass is 439 grams/mole (from the periodic table), so 18.8 grams of it is 0.0428 moles (by algebraic direct proportion). Multiply this by Avogadro's number (6.02x1023; the number of particles in 1 mole) and you get 2.58x1022 formula units of barium nitride, and there are 2 nitrogen atoms per formula unit, so double it to 5.16x1022 atoms of nitrogen.