the answer is 4.0 g
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Divide 96 by molecular mass.So the answer is 6mol
The atomic mass of the organic compound CH3OH is 12.0 + 3.0 + 16.0 + 1.0 = 32.0Amount of CH3OH = mass of pure sample/molar mass = 5.00/32.0 = 0.156molThere are 0.156 moles of CH3OH in a 5.00 gram pure sample.
Divide 2.52 by molecular mass 16.Then multiply by avagadro constant
The answer depends on sample of WHAT!
Take the balanced equation CH4+2O2---->CO2+2H2O.So according to it 40g of O2
300K
5600
Divide 96 by molecular mass.So the answer is 6mol
The atomic mass of the organic compound CH3OH is 12.0 + 3.0 + 16.0 + 1.0 = 32.0Amount of CH3OH = mass of pure sample/molar mass = 5.00/32.0 = 0.156molThere are 0.156 moles of CH3OH in a 5.00 gram pure sample.
7.48
Divide 2.52 by molecular mass 16.Then multiply by avagadro constant
The volume of a sample of water is 20 cm3. The mass of this sample is closest to
The answer depends on sample of WHAT!
This mass is 6,416 g.
The property that depends on the size of the sample is extensive. Extensive properties, such as mass and energy, scale with the size of the sample. This means that as the sample size increases, the value of the property also increases proportionally.
Mass is an extensive property, which depends only on the amount of matter in the sample, not on the composition of the sample.
Take the balanced equation CH4+2O2---->CO2+2H2O.So according to it 40g of O2