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4 times the Atomic Mass of hydrogen plus the atomic mass of carbon, or (4 X 1.008) + 12.011, or 16.043.
What else can I help you with?
How many moles of CH4 are present in 6.07 g of (CH4)?
Divide 96 by molecular mass.So the answer is 6mol
How many moles of CH4 are in 200 grams of CH4?
200 g CH4 x 1 mole CH4/16 g = 12.5 moles CH4
What mass of oxygen is required to completely react with 20 grams of CH4?
To calculate the mass of oxygen required to react with 20 grams of CH4, we first need to write and balance the chemical equation for the reaction. The balanced equation for the combustion of CH4 is: CH4 + 2O2 → CO2 + 2H2O This equation tells us that 1 mole of CH4 reacts with 2 moles of O2. The molar mass of CH4 is 16 g/mol. Therefore, 20 grams of CH4 is equal to 20/16 = 1.25 moles CH4. So, 1.25 moles of CH4 would require 2.50 moles of O2. The molar mass of O2 is 32 g/mol. Therefore, the mass of O2 required would be 2.50 moles * 32 g/mol = 80 grams.
- If the mass of 0.8 moles mixtures of NO and CH4 gases is 17 grams;I. The number of moles of NO is greater than the number of moles of CH4II. CH4 in the mix is 8 grams.III. NO in the mix is 0.3 mole?
I. False - Since both gases contribute to the total mass, the number of moles of NO does not necessarily need to be greater than the number of moles of CH4. II. True - If the total mixture mass is 17 grams and CH4 is 8 grams, then the remaining mass must be of NO. III. True - If the total moles of the mixture is 0.8, and CH4 is 0.5 moles (8g/16 g/mol), then the moles of NO would be the remaining 0.3 moles.
How many moles of oxygen will be needed to completely oxidize 64g CH4?
Molar mass:O2 32 g/molCH4 16 g/molReaction:CH4 + 2 O2 --> CO2 + 2H2OCalculus1 mol CH4 with 2 moles O2Given: 24 g CH4 equals 24/16 = 1.5 mol CH4this will need 2 * 1.5 moles O2 = 3.0 mol O23.0 mol O2 equals 3.0 * 32 = 96 g O2
How many moles of CH4 are present in 6.07 g of (CH4)?
Divide 96 by molecular mass.So the answer is 6mol
How many moles of CH4 are in 200 grams of CH4?
200 g CH4 x 1 mole CH4/16 g = 12.5 moles CH4
What mass of oxygen is required to completely react with 20 grams of CH4?
To calculate the mass of oxygen required to react with 20 grams of CH4, we first need to write and balance the chemical equation for the reaction. The balanced equation for the combustion of CH4 is: CH4 + 2O2 → CO2 + 2H2O This equation tells us that 1 mole of CH4 reacts with 2 moles of O2. The molar mass of CH4 is 16 g/mol. Therefore, 20 grams of CH4 is equal to 20/16 = 1.25 moles CH4. So, 1.25 moles of CH4 would require 2.50 moles of O2. The molar mass of O2 is 32 g/mol. Therefore, the mass of O2 required would be 2.50 moles * 32 g/mol = 80 grams.
- If the mass of 0.8 moles mixtures of NO and CH4 gases is 17 grams;I. The number of moles of NO is greater than the number of moles of CH4II. CH4 in the mix is 8 grams.III. NO in the mix is 0.3 mole?
I. False - Since both gases contribute to the total mass, the number of moles of NO does not necessarily need to be greater than the number of moles of CH4. II. True - If the total mixture mass is 17 grams and CH4 is 8 grams, then the remaining mass must be of NO. III. True - If the total moles of the mixture is 0.8, and CH4 is 0.5 moles (8g/16 g/mol), then the moles of NO would be the remaining 0.3 moles.
What mass of CO2 is produced in the reaction of 4 moles of CH4 in excess O2?
For every 1 mole of CH4 that reacts, 1 mole of CO2 is produced. Therefore, 4 moles of CH4 will produce 4 moles of CO2. To calculate the mass of CO2 produced, you would need to multiply the moles of CO2 by its molar mass (44 g/mole) to get the total mass produced.
How many moles of oxygen will be needed to completely oxidize 64g CH4?
Molar mass:O2 32 g/molCH4 16 g/molReaction:CH4 + 2 O2 --> CO2 + 2H2OCalculus1 mol CH4 with 2 moles O2Given: 24 g CH4 equals 24/16 = 1.5 mol CH4this will need 2 * 1.5 moles O2 = 3.0 mol O23.0 mol O2 equals 3.0 * 32 = 96 g O2
What is the mass of 5.0 moles of CH4?
The atomic mass of the organic compound CH3OH is 12.0 + 3.0 + 16.0 + 1.0 = 32.0Amount of CH3OH = mass of pure sample/molar mass = 5.00/32.0 = 0.156molThere are 0.156 moles of CH3OH in a 5.00 gram pure sample.
How many moles in 64 grams of CH4?
There are 0.75 moles in it.You have to devide 12 by molecular mass
What mass of water is produced from the complete combustion of 2.50x10-3 of methane?
Methane is CH4. Combustion is CH4 + 2O2 ==> CO2 + 2H2O1 mole CH4 produces 2 moles H2Omoles CH4 used = 1.1x10^-3 g x 1 mole/16 g = 6.875x10^-5 molesmoles H2O produced = 6.875x10^-5 moles CH4 x 2 moles H2O/mole CH4 = 1.375x10^-4 molesmass H2O produced = 1.375x10^-4 moles x 18 g/mole = 2.475x10^-3 g = 2.48 mg (3 sig.figs)
What is the weight in grams in o.4 moles of CH4?
This mass is 6,416 g.
How many moles in 2.8mol CH4?
2,8 moles is of course equivalent to 2,8 moles !Probable is a spelling error in your question.
Are there two moles in CH4?
That's a tricky question, because one molecule of CH4 is simply that, one atom of carbon and 4 atoms of Hydrogen. Moles are a UNIT used to transform atoms (which we cannot measure individually in the lab) into practical units such as grams (which we can measure). The moles of CH4 depend on the mass, in SI units of grams, that you have of this substance. The molecular weight of CH4 is 16 g/mol (12 for Carbon + 1 for each Hydrogen). If you WANTED 2 moles of CH4, you need to multiply this molecular weight by 2 moles to get 32 grams (the moles cancel out upon multiplication). So, 32 grams of CH4 is 2 moles of CH4.
