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Molarity = moles of solute/volume of solution.
0.73 grams MgCl2 (1mol/95.21g ) = 0.00767 moles/0.300 Liters ( to get M, not mM )
= 2.6 X 10^-2 M
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What is the molarity of a solution dissolve 0.31 grams of HNO3 in 300ml of water?
Molarity = moles of solute/Liters of solution ( get moles of HNO3 and 300 ml = 0.300 Liters ) 0.31 grams Nitric acid (1 mole HNO3/63.018 grams) = 0.004919 moles HNO3 Molarity = 0.004919 moles HNO3/0.300 Liters = 0.0164 M HNO3
What is the molarity of srno32 in a solution resulting from mixing 150.0 ml of 0.0200 m hno3 with 150.0 ml of 0.0100 m sroh2?
You get 300 mL of 0.0100 M Sr(NO3)2 solution
How would you prepare a 300 ml of a 0.1 M Na CL solution from a solid Na CL solution and water?
You prepare a solution by dissolving a known mass of solute into a specific amount of solvent. In solutions, M is the molarity, or moles of solute per liter of solution. For 300 ml of a 0.1 M Na CL solution from a solid Na CL solution and water you need water and sodium chloride.
How much NaCl precipitate would be produced if 2 molarity HCl and 1 molarity sodium carbonate react in the reaction Na2CO3 plus 2HCL yeilds 2NaCl plus H2O plus CO2?
The resulting product would be a roughly 2 M NaCl solution (slightly less than 2 molar because the solution is diluted by the water that is produced by the reaction). 2 M HCl + 1 M Na2CO3 --> 2 M NaCl + 1 M H2O + 1 M CO2 Two moles of NaCl weigh about 117 g (58.5 grams per mol) so the resulting solution has a sodium chloride concentration of about 117 grams per liter. This concentration is well below the maximum solubility of water at room temperature and atmospheric pressure ( > 300 g/liter) so there would not be any NaCl at all precipitating. The answer is thus: no NaCl precipitate will form.
Please show work How many moles would there be in 300 ml of of a 1.5 M solution?
300 (mL) * 1.5 (mol/L) * 1 (L) / 1000 (mL) = 0.45 mol
Calculate molarity of solution containing 16 gm glucose per 300 ml solution?
Can u answer this Question
What is the molarity of a 3000 liters solution containing 300 grams of NaCl?
Molarity = moles of solute/Liters of solution Find moles NaCl 300 grams NaCl (1 mole NaCl/58.44 grams) = 5.13347 moles NaCl Molarity = 5.13347 moles NaCl/3000 Liters = 1.71 X 10^-3 M sodium chloride ----------------------------------------
What is the molarity of a solution dissolve 0.31 grams of HNO3 in 300ml of water?
Molarity = moles of solute/Liters of solution ( get moles of HNO3 and 300 ml = 0.300 Liters ) 0.31 grams Nitric acid (1 mole HNO3/63.018 grams) = 0.004919 moles HNO3 Molarity = 0.004919 moles HNO3/0.300 Liters = 0.0164 M HNO3
What is the molarity of srno32 in a solution resulting from mixing 150.0 ml of 0.0200 m hno3 with 150.0 ml of 0.0100 m sroh2?
You get 300 mL of 0.0100 M Sr(NO3)2 solution
How many moles of potassium hydroxide are required to prepare 300 mL of 0.250 M solution?
Molarity = moles of solute/liters of solution ( 300 ml = 0.300 liter ) 0.250 molar KOH = moles KOH/0.300 liters = 0.075 moles KOH
How would you prepare a 300 ml of a 0.1 M Na CL solution from a solid Na CL solution and water?
You prepare a solution by dissolving a known mass of solute into a specific amount of solvent. In solutions, M is the molarity, or moles of solute per liter of solution. For 300 ml of a 0.1 M Na CL solution from a solid Na CL solution and water you need water and sodium chloride.
How many grams of sodium chloride is in 0.40 moles?
Molarity = moles of solute/Liters of solution ( 300 ml = 0.300 Liters ) For our purposes, Moles of solute = Liters of solution * Molarity Moles NaCl = 0.300 Liters * 0.15 M = 0.05 moles NaCl =============
How many sugar molecules are present in 300 mL of a 2.0 molar solution?
By the definition of molarity, a 2.0 molar solution contains twice Avodagro's Number of molecules per liter. Therefore, the stated solution contains 0.300X2X6.022Xten to the 23rd power = 3.6X ten to the twenty-third power sugar molecules. (Only two significant digits are justified, because the molarity is specified with only two significant digits.)
What quantity of a 80 percent acid solution must be mixed with a 30 percent solution to produce 300 mL of a 40 percent solution?
Let Q be the quantity of 80% solution required then (300 - Q) is the quantity of 30% solution as together the two solutions must equal 300. Then, [80 x Q] + [30 x (300 - Q)] = [40 x 300] 80Q + 9000 - 30Q = 12000 50Q = 3000 Q = 60...........which means (300 - Q) = 240 60ml of 80% acid solution + 240ml of 30% solution produces 300ml of 40% solution.
What is the ditloid solution to - 300 L of NA in C?
300 Length of Noah's Ark in Cubits
Can 16 go into 300 evenly?
No, 18.75 is the solution.
What is the answer to 300 - 5t?
295
