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A: 10.172 M HCl.

Percents of acids like this one is normally given in % w/w, or percent weight by weight. So we need to find the mass of the solution.

Molarity is moles of solute per liter solution, so we will calculate this for 1L of solution.

The density of 32% HCl is 1.159 g/mL. So assuming we have one liter or 1000 mL, the weight of the solution is 1159 g. If 32% of this is HCl, we have 1159 g solution * 0.32 g HCl/g solution = 370.88 g HCl.

The molar mass of HCl is 36.461 g/mol, so 370.88 g HCl * 1 mol HCl/36.461 g HCl = 10.172 mol HCl in 1 L of solution.

10.172 mol HCl/1L solution = 10.172 M HCl.

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13y ago
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12y ago

The molarity can be calculated from the exact assay value (for example 35% here) and the density of the HCl ( 1.18 gm/ml). It may vary a little for different lots of the acid according to the exact assay value taking upto two decimal point value.

If we take the above values the molarity or normality becomes around 12.

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Q: What is the molarity of 32 percent HCl?
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