A: 10.172 M HCl.
Percents of acids like this one is normally given in % w/w, or percent weight by weight. So we need to find the mass of the solution.
Molarity is moles of solute per liter solution, so we will calculate this for 1L of solution.
The density of 32% HCl is 1.159 g/mL. So assuming we have one liter or 1000 mL, the weight of the solution is 1159 g. If 32% of this is HCl, we have 1159 g solution * 0.32 g HCl/g solution = 370.88 g HCl.
The molar mass of HCl is 36.461 g/mol, so 370.88 g HCl * 1 mol HCl/36.461 g HCl = 10.172 mol HCl in 1 L of solution.
10.172 mol HCl/1L solution = 10.172 M HCl.
The molarity can be calculated from the exact assay value (for example 35% here) and the density of the HCl ( 1.18 gm/ml). It may vary a little for different lots of the acid according to the exact assay value taking upto two decimal point value.
If we take the above values the molarity or normality becomes around 12.
Sumodhur
Molarity = moles of solute/Liters of solutionSo, get moles HCl.73 grams HCl (1 mole HCl/36.458)= 2.00 moles HCl---------------------------Molarity = 2.00 moles HCl/2 Liters= 1 M HCl=======
Molarity = moles of solute/liters of solution Molarity = 0.597 moles HCl/0.169 liters = 3.53 M HCl ------------------
Find moles of HCl first. 1.56 grams HCl (1mole HCl/36.458 grams) = 0.0428 moles HCl Molarity = moles of solute/volume of solution Molarity = 0.0428 moles/26.8 ml = 0.00160 milli-Molarity, or more to the point; = 1.60 X 10^-6 Molarity of HCl
Factor in hcl ?
1.22Molarity (multiply) 0.076Liters = 0.09272Moles needed to neutralize. 0.09272Moles (divided by) 0.125Liters = 0.74176 Molarity HCl has a Molarity of 0.74176
6M
Molarity = moles of solute/Liters of solutionSo, get moles HCl.73 grams HCl (1 mole HCl/36.458)= 2.00 moles HCl---------------------------Molarity = 2.00 moles HCl/2 Liters= 1 M HCl=======
Molarity = moles of solute/liters of solution Molarity = 0.597 moles HCl/0.169 liters = 3.53 M HCl ------------------
Find moles of HCl first. 1.56 grams HCl (1mole HCl/36.458 grams) = 0.0428 moles HCl Molarity = moles of solute/volume of solution Molarity = 0.0428 moles/26.8 ml = 0.00160 milli-Molarity, or more to the point; = 1.60 X 10^-6 Molarity of HCl
Factor in hcl ?
1.22Molarity (multiply) 0.076Liters = 0.09272Moles needed to neutralize. 0.09272Moles (divided by) 0.125Liters = 0.74176 Molarity HCl has a Molarity of 0.74176
37% HCL equals to 12.18 M. So you can caculate 32% is 10.53 M. That means for preparing 1 L 1.5 M HCL, you need mix 142.45 mL 32% with 857.55 mL dH2O.
The molarity is 0,041
31 grams HCl (1mol/36.458g ) = 0.850 moles 500cm^3 = 0.50 Liters Molarity = moles of solute/liters of solution Molarity = 0.850mol/0.50L = 1.7 Molarity
The HCL concentration is 1.2M or 1.2N
We can use PV = nRT to find moles of HCl (1 atm)(4.60 L) = n(0.08206 L*atm/mol*K)(298.15 K) moles HCl = 0.188 moles Molarity = moles of solute/Liters of solution Molarity = 0.188 moles HCl/0.240 liters = 0.783 Molar HCl =============
Molarity = moles of solute/Liters of solution Molarity = 6 Moles NaCl/2 Liters = 3 M NaCl ========