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How many ml of 1 M stock solution of Na Cl are needed to prepare 200 ml of a 0.05 M solution?
Wiki User
∙ 14y ago
Molartiy = moles of solute/Liters of solution
200 mL X (1 Liter/10^2)= 0.200 Liters
0.200 Liters x (0.05 M)= .01 moles of NaOH
.01 moles of NaOH x (40 g NaOH/ 1 mole NaOH)= 0.4 g NaOH are required
Wiki User
∙ 11y ago
Wiki User
∙ 14y ago(ml NaCl )(1M NaCl) = (200ml NaCl )(0.05M NaCl )
= 10 ml
Wiki User
∙ 13y agoAs %age=mass/volume*100, so
2.5=m/2.5*100, or
m=0.025*2.5=0.0625g
Wiki User
∙ 10y agoThe definition of molarity is moles per litre. Therefore 200x5 is 1 litre. 0.5*5 is 2.5 moles. This is per litre. I.e. 2.5 molar.
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The needed mass is 35,549 g.
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4 moles or 160 g NaOH is required for one litre solution.
How many grams of KCl are needed to prepare 125 mL of a 0.720 M KCl solution?
The answer is 6,71 g dried KCl.
How many moles of HNO3 are needed to prepare 5.0 liters of 2.0m soultion of HNO3?
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