Potassium sulfate = K2SO4
[2K+]tribunated + 2I-(aq) + Cu2+(aq) + [SO42-]tribunated --> --> CuI2(s) + [2K+ + SO42- ]tribunated
Potassium Hydroxide(KOH) is a base (it is "basic"). An acid will neutralize a base. Acetic acid can be used to neutralize KOH. Baking soda is a base, so it will not work to neutralize KOH.
In the acid-base reaction where sodium hydroxide and sulfuric acid react, the formula is: H2SO4 + 2NaOH --> Na2SO4 + 2H2O. The coefficients shown are necessary to uphold the law of conservation of mass. So, if you have 17 moles of sulfuric acid, you will need twice as many moles of sodium hydroxide, so the answer is 34 moles NaOH.
The salt formed by the reaction of calcium hydroxide and sulfuric acid is calcium sulfate. The formula of this salt is CaSO4. Calcium sulfate is a white in appearance when pure.
Sulfur is used in gun powder and other explosives.
Potassium sulphate and water: H2SO4 + 2 KOH----------K2SO4 + 2H2O
H2so4 +2koh>k2so4+2h2o
No, this is a neutralization reaction 2NaOH + H2SO4 --> Na2SO4 + 2H2O An ionic salt (dissolves in solution ) and water produced.
The acid that reacts with lithium hydroxide in a neutralization reaction to form lithium sulfate and water is sulfuric acid (H2SO4).
Potassium Sulfate and water
H2SO4 + 2NaOH --> Na2SO4 + 2H2O
Na2SO3(aq) and H2O(l)
sulphuric acid
Potassium hydroxide is a strong alkali. Therefore it can be neutralized by using a strong acid such as nitric acid or sulfuric acid.
Actually there are two possibillities:K2SO4, potassium sulfate, when 1 mole sulfuric acid is added to 2 moles potassium hydroxide 2 KOH + H2SO4 ------> K2SO4 + 2 H2OorKHSO4, potassium hydrogen sulfate (-bisulfate), when 1 mole sulfuric acid is added to 1 mole potassium hydroxide 1 KOH + H2SO4 ------> KHSO4 + H2O
2 KOH + H2SO4 --> 2 H2O + K2SO4 Potassium Hydroxide + Sulfuric Acid --> Water + Potassium Sulfate.
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