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What is the net resistance of two resistor connected in series?
Paadusha
The net resistance of two resistors connected in series is the sum of the two resistances.
RSERIES = Summation1toN RN
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∙ 12y ago
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What is practical voltage source?
in case of ideal voltage source we consider the internal resistance to be zero.but in practical,every battery has some internal resistance then if you connect a load resistance across the terminals of that source,the net potential difference's across the voltage source will be a function of external resistance connects it won't give constant voltage across it's terminals.
What advantage might there be in using two identical capacitors in parallel connected in series with another identical parallel pair rather than a single capacitor?
I honestly think thst people should stop searching for assignment answers on the net. study your books and the given texts for reference to the given questions.
What happens to the current in a circuit if one resistance is doubled or halved?
P1 = V I1, Therefore, if P2=0.5*P1, thenI2=0.5*P1/V, or 0.5*I1and if P3=2*P1, thenI3=2*P1/V, or 2*I1In other words, current is proportional to power and inversely proportional to voltage.
Why at resonance the voltage drop across inductance and the voltage drop across capacitance is greater than the source voltage?
This isn't necessarily the case. It depends upon the value of resistance (which, at resonance, determines the current), and the values of the inductive- and capacitive-reactance.At resonance, the impedance of the circuit is equal to its resistance. This is because the vector sum of resistance, inductive reactance, and capacitive reactance, is equal the the resistance. This happens because, at resonance, the inductive- and capacitive-reactance are equal but opposite. Although they still actually exist, individually.If the resistance is low in comparison to the inductive and capacitive reactance, then the large current will cause a large voltage drop across the inductive reactance and a large voltage drop across the capacitive reactance. Because these two voltage drops are equal, but act the opposite sense to each other, the net reactive voltage drop is zero.So, at (series) resonance:a. the circuit's impedance is its resistance (Z = R)b. the current is maximumc. the voltage drop across the resistive component is equal to the supply voltaged. the voltage drop across the inductive-reactance component is the product of the supply current and the inductive reactancee. the voltage drop across the capacitive-reactance component is the product of the supply current and the capacitive reactancef. the voltage drop across both inductive- and capacitive-reactance is zero.
Why do the amps in a circuit decrease as you add more wire?
They don't. the voltage decreases & the amps will increase. The longer the wire the more resistance the less voltage. In order for you power, KW or VA to remain the same, if your voltage drops your amps go up, if your voltage goes up your amps will drop. (I=P/E),(P=ExI)(E=P/I)I=ampsE=voltsP=power or watts or better yet VAThe answer above presumes that KW or VA remains the same in a circuit regardless of what you do to it. They do not. I do not intend to be argumentative but here is my answer.Adding resistance IN SERIES with a circuit decreases the amps that would otherwise flow because it has to overcome more resistance. Since conductors have resistance and are by their very nature IN SERIES with a load, adding length to conductors can, does, and will decrease the amps across the entire circuit.If you aren't into reading technical descriptions, stop reading now. The simple answer is in my second paragraph above, and is all you probably needed or wanted to know.What confuses people is how the circuit behaves when you add another load IN PARALLEL, which is how most circuits you and I use are wired. Adding a load IN PARALLEL will increase the amps of the overall circuit because it decreases the net resistance of the circuit. The best comparison that will help you understand this is a water line. If a water line has two faucets with only one faucet open, you have a certain amount of pressure inside to water pipe. If you open both faucets you now have more water flowing and a net decrease in pressure within the pipe. Comparing a circuit to a water pipe in this manner is not far fetched. It is exactly how and why you get more amps when you add lights to a circuit. They are connected IN PARALLEL to each other.Getting back to our conductors, however, you can see that the first leg of conductors from the breaker to the first load is carrying the amps of the whole circuit. Each leg from one load to another carries decreasing amps because it is carrying amps to fewer loads. The amount of power lost in these conductors is equal to I2R. Plugging in this value to the other formulas allows you to calculate how much voltage is "dropped" across any leg of the circuit, knowing the voltage applied and getting the resistance of the conductors from the code book.As always, if you are in doubt about what to do, the best advice anyone should give you is to call a licensed electrician to advise what work is needed.Before you do any work yourself,on electrical circuits, equipment or appliances,always use a test meter to ensure the circuit is, in fact, de-energized.IF YOU ARE NOT ALREADY SURE YOU CAN DO THIS JOBSAFELY AND COMPETENTLYREFER THIS WORK TO QUALIFIED PROFESSIONALS.
When 10 ohm resistance and 100 mega ohm resistance are connected in series then what will be their conbined resistance?
The net effective resistance of resistors in series is the sum of the individuals.Combined resistance = (100,000,000) + (10) = 100,000,010Ωhms.
How do resistors act in series?
In brief, the overall or net resistance changes and the resistors in series and/or parallel can be represented by a single equivalent resistor. If you consider series resistors the equivalent resistance of the series would be: R = R1+R2+ ... +Rx The equivalent resistance of parallel resistors would be: 1/R = 1/R1 + 1/R2 + ... + 1/Rx One rule to always remember when dealing with series and parallel resistors is the voltage across each resistor in parallel will be the same as defined in Kirchhoff Voltage Law and the current across each resistor in series will be the same by Kirchhoff Current Law. More information can be found at this web site. http://physics.bu.edu/py106/notes/Circuits.html
What is the current in a 12-volt circuit with two 6-ohm resistor connected in parallel?
Two 6-ohm resistors in parallel have a net effective resistance of 3 ohms.With 3 ohms connected across a 12-volt supply, the current is 12/3 = 4 amperes.
How are parallel resistors connected?
If you need a resistor of a certain value, and you have no resistors with small enough values,you can create the one you need by connecting several of those you have in parallel.The effective net resistance of resistors in parallel is always less than the smallest individual.And the more resistors you add in parallel, the smaller the net effective resistance becomes.
What happens when resistors are interconnected in a circuit?
The net resistance can be found out using the algebraic sums f series and parallel connections. When there is no current flowing in the circuit the net resistance is infinite.
Why you use resistor with variable resistor?
Often we want to easily change a resistor value, so we use a variable resistor. For example, we may want to change the resistor that controls the power sent to a LED, so we can easily make it brighter or dimmer. Often if we use a variable resistor, there is only a very narrow range that is useful. Continuing our example, sometimes we use several LEDs, and we use the variable resistor to set them all to the same brightness. In this case, the resistance range that sets the LED to be twice as bright as the the other LEDs, and the resistance range that sends so much power to the LED that it is permanently destroyed is even less useful. So we add a fixed resistor in series with the variable resistor -- the fixed resistor sets the minimum net resistance, no matter how we turn the knob on the variable resistor. In our example, the addition of the fixed resistor allows us to turn the variable resistor throughout its whole range, and the LED gets brighter and dimmer; without that resistor, a certain range of the knob on the variable resistor would allow so much power to go to the LED that it would be destroyed.
How do you calculate the equivalent resistance of a circuit of the shape of a cube and a having a resistor of i kilo ohm in every branch?
Given twelve 1 KOhm resistors, connected in the shape of a cube, in order to determine the net resistance between opposite corners, first draw the cube in two dimensions. (Try this at each step before continuing, so you can understand the lesson as it unfolds.)There are three resistors leaving the initial vertex, and three resistors entering the final vertex. In between those six resistors, are six more resistors, each pair connected together on one end, and to two other resistors on the other end.If every resistor has the same value, then (by symmetry), the voltage on the ends of the first three resistors must be the same. Similarly, the voltage on the ends of the last three resistors must be the same.If two points in a circuit have the same voltage, then (for purposes of analysis) you can consider them to be shorted together. That short does not change the results, as there is no current flowing through that short.With the bottom ends of the first three resistors shorted, and with the top ends of the last three resistors shorted, the circuit degrades into three resistors in parallel, in series with six more resistors in parallel, in series with three more resistors in parallel.Three 1 KOhm resistors in parallel have a net resistance of 333 ohms. Six have a net resistance of 167 ohms. Two 333 ohm resistors and one 167 ohm resistor in series have a net resistance of 833 ohms, or 5/6 of 1 KOhms.Note: This technique does not work if the resistors are not all the same value. In that case, you would need to solve 12 equations in 12 unknowns, looking at the partial currents in each branch.
Why the net resistance increases in series connection?
series network consists of components i.e resisters connected end to end. since their is only one path for the flow of current. but potential drop across each resister is different. so thats the reason that series network has maximum resistence then the highest resister in combination. the same amount of current passes through each resister.
If 3 15 ohm resistors are connected in parallel to a 30 volt battery what is the equvalent resistance through the circuit?
5 ohms...
A circuit contains two devices that are connected in parallelIf the resistance of one of these device is 12 ohms and the resistance of the other device is 4 ohms the total resistance of the two divice?
For resistances in parallel, total effective resistance is [ 1 divided by (1/R1 + 1/R2 + 1/R3 + . . . . . etc.) ]For two resistors, this expression can be massaged to show that the net effective resistance is(R1 R2) / (R1 + R2).(12 x 4) / (12 + 4) = 48/16 = 3 ohms.
A circuit contains two devices that are connected in parallel if the resistance of one of these devices is 12 ohms and the resistance of the other device is 4 ohms the total resistance of the two devi?
The net effective resistance of the parallel devices is the reciprocal of (1/12 + 1/4). Hence 3 ohms.=============================================(Which actually looks strangely similar to the first answer above.Could it be just coincidence ? I wonder . . . )
What is the net force when encounters 15 N air resistance?
15N
