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There is 9.2758% Al3+ in a formula unit of aluminum oxide.
AnswerThe formula for aluminum oxide is Al2O3: Molar mass =581.77g/mol Al2O3.In one mole Al2O3, there are two moles of Al3+ ions, therefore 2 moles Al3+ x 26.982g/mol Al3+ = 53.964g Al3+ in one mole of Al2O3.
GIVEN: mass of Al3+ = 53.964 gAl3+;Molar mass of Al2O3 = 581.77 gAl2O3
WANTED: % Al3+
EQUATION:
% Al3+...=...g Al3+x 100...g Al2O3
% Al3+...=...53.964gAl3+x100......=...9.2758%Al3+581.77g Al2O3
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∙ 12y ago
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∙ 15y agoAluminum Phosphate- AlPO4
Find the atomic masses for each element and multiply it by the number of atoms in the compound, then add.
Al- 27.0
P- 31.0
O- 16.0 * 4= 64.0
------------------------
122.0
Take the masses for each element and divide them by the total mass. Then change the answer to a percent.
Al 27.0 / 122.0= .221 = 22.1%
P- 31.0 / 122.0= .254= 25.4%
O- 64.0 / 122.0= .525= 52.5%
There is 22.1% of Aluminum, 25.4% of Phosphate, and 52.5% of Oxygen in Aluminum Phosphate.
Wiki User
∙ 10y agoAl is a metal, and thus wants to lose electrons to become like a noble gas, so it loses 3 electrons to have a [Ne] configuration, which we write as Al3+. Sulfate (SO4) has a 2- charge. Thus in order to get a neutral charge, the chemical formula for Aluminum sulfate must be Al2(SO4)3. Atomic Mass of each atom is added to get the formula mass. (Al = 27.0 g/mol * 2 atoms) + (3 * [S = 32.1 g/mol + O = 16.0 * 4 atoms]) = 342.3 g/mol
% mass of Al = (2 atoms * 27.0 g/mol) / (342.3 g/mol) = 15.77%
Wiki User
∙ 13y agothe percentage composition of aluminum sulfate is 342
Wiki User
∙ 13y agoMr (Al2(SO4)3 ) = (2 x 27) + (3 x (32 + (4 x 16) ) ) = 342
Mr (Al) = 27
% by mass of Aluminum = (27/342) x 100 = 7.89%
Wiki User
∙ 11y agoAluminium sulfate is Al2(SO4)3 and its molecular weight is 342.15 g/mol. There are 12 oxygens present.
So the percentage of oxygen = (12 x 16) / 342.15 = 0.561 or 56.1%
Wiki User
∙ 9y ago15.77%
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What is the percent composition of CH3CH2OH?
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s 50% o 50%
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what trinitrotoluene percent composition?
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For a total mass of water weighing 190 g the mass of H is 21 g and the mass of O is 169 g What is the percent composition of O in water?
88.5%
What is the percent composition by mass of C10H14O?
Percent composition means finding the total mass of each element in a molecule and then dividing it by the molecular mass. Use the molecular formula to help you find out how many atoms of each element you'll need. For carbon: 6 C x 12 g = 72 g For hydrogen: 10 H x 1 g = 10 g For oxygen: 5 O x 16 g = 80 g Molecular mass = C + H + O = 72 + 10 + 80 = 162 g Percent composition of C = 72/162 = 0.4444 = about 44.45% Percent composition of H = 10/162 = 0.061728395 = about 6.17% Percent composition of O = 80/162 = 0.49382716 = about 49.38%
