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The percentage of nitrogen in aluminium nitrate is 19,72 %.
NH3 which is ammonia has the highest percentage by mass of nitrogen.
Relative atomic mass: Zinc= 65 Nitrogen= 14 Oxygen= 16 Nitrate= nitrogen and oxygen= 30 Formula for zinc nitrate: Zn(NO3)2 NO= 30 NO3= 90 Zn= 65 Zn(NO3) x2 = Zn(NO3)2= 310 Formula mass (molecular mass)(Mr) of zinc nitrate = 310
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The percentage of nitrogen is 29,16 %.
The percentage of nitrogen in aluminium nitrate is 19,72 %.
# of AtomsAt Wt.Total Wt.Nitrogen214.006728.0134Hydrogen41.007944.03176Oxygen315.999447.9982Total Molecular weight80.04% of Nitrogen=28.01/80.04 = 35%
The relative molecular mass of Ca(NO3)2, also known as calcium nitrate, can be calculated by adding the atomic masses of calcium (Ca), nitrogen (N), and three oxygen (O) atoms. The atomic masses are 40.08 g/mol for calcium, 14.01 g/mol for nitrogen, and 16.00 g/mol for oxygen. When you add these values together, the relative molecular mass of Ca(NO3)2 is 164.08 g/mol.
off the top of my head = 102Let's break this down. Very easy- first, take the #atoms of each element, 1 calcium,2 nitrogen, 6 oxygen. You can pull these straight off of the chemical formula. Now, multiply by molar mass- on the periodic table. (calcium) 1*40.078=40.078, (Nitrogen) 2*14.0067=28.0134, (Oxygen) 6*16=96. Now, add 'em up. 40.078+28.0134+96=164.0914 (Grams/mole)nothing to it.
Mass of Nitrogen: 14g/mol Mass of Ammonium Nitrate (NH4NO3): 14 + 1x4 + 14 + 16x3 = 80g/mol ∴ % of Nitrogen in Ammonium Nitrate = 14/80 * 100 = 17.5%
The formula for sodium nitrate is NaNO3, showing that each formula unit contains one sodium atom, one nitrogen atom, and three oxygen atoms. The gram atomic masses of sodium, nitrogen, and oxygen are 22.9898, 14.0067, and 15.9994 respectively. Therefore, the percentage by mass of nitrogen in the compound is: 100{14.0067/[14.0067 + 22.9898 + 3(15.9994)]} or about 16.4795, to the justified number of significant digits.
NH3 which is ammonia has the highest percentage by mass of nitrogen.
Ammonium Nitrate = NH4NO3 or N2H4O3 the total mass of a ammonium nitrate molecule is as follows: 2*14u + 4*1u + 3*16u = 28u + 4u + 48u = 80u now, the total mass of Nitrogen in one ammonium nitrate is 2*14u = 28u. Then, we divide 28 (the mass of Nitrogen) by 80 (total mass)= 28/80 = 0.35, which is the ratio for Nitrogen mass divided by total mass. then, we get the 48.5 grams (total mass) and multiply it by this ratio (0.35): 48.5 * 0.35 = 16.975 grams of Nitrogen in 48.5 grams of Ammonium Nitrate.
The mass of silver nitrate is 30,6 g.
Ammonia contains about 82.35 % nitrogen by mass.
Relative atomic mass: Zinc= 65 Nitrogen= 14 Oxygen= 16 Nitrate= nitrogen and oxygen= 30 Formula for zinc nitrate: Zn(NO3)2 NO= 30 NO3= 90 Zn= 65 Zn(NO3) x2 = Zn(NO3)2= 310 Formula mass (molecular mass)(Mr) of zinc nitrate = 310
Sodium nitrate is NaNO3. The percent nitrate is given by :PCT Nitrate = [ ( 14 + 48 ) / ( 23 + 14 + 48 ) ][ 100 ] = [ 62 /85 ][ 100 ] = 72.94 mass percent