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mov r1r2 is invalid instruction because of there is no communication with ALU in its operation;
mov H , L mov is opcode H L are operands
•The mov instruction carries out assignment in 8086 assembly language. •It which allows us place a number in a register or in a memory location (a variable) i.e. it assigns a value to a register or variable. Example: Store the ASCII code for the letter A in register bx.•A has ASCII code 65D (01000001B, 41H) •The following mov instruction carries out the task:•mov bx, 65d•We could also write it as:•mov bx, 41h•or mov bx, 01000001b•or mov bx, 'A'
1byte instruction = MOV A,B 2byte instruction = MVI A,01H 3byte instruction = STA 2030H
mov
The MOV A,B instruction requires 1 machine cycle and 4 T-states, 3 to fetch the opcode, and 1 to decode/execute it.
Syntax error: incomplete instruction.
This actually depends on the processor you are referencing; some processors update their IP (Instruction Pointer) before performing a command, and some perform it after the command. To find out if your processor is doing so before or after the command, use the instruction "mov ax,ip" in a debugger, and observe the value of ax. If ax contains the address of the mov instruction, it performs the update of IP after processing a command, while if it contains the address after the mov instruction, it performs the update before processing the command.
In the 8085 microprocessor, the MOV instruction copies data between two registers, or between a register and memory. The MVI instruction differs only in that the source data is contained in the byte immediately following the opcode byte.
The MOV A,A instruction in the 8085 does nothing, not even change flags. It only consumes time, specifically four clock cycles plus applicable wait states.
The instruction 20H is RIM (Read Interrupt Mask). The instruction 57H is MOV D,A. The contents of PC after these two instruction will be 2 greater than it was before starting.
mov ax:[008D] mov [00B3]:ax