If you put them in water, then they both separate and the chloried and nitrate switch places. It becomes Magnesium nitrate and lead chloride, one turns yellow and sinks while the other's clear and floats. I think. If you put them in water, then they both separate and the chloried and nitrate switch places. It becomes Magnesium nitrate and lead chloride, one turns yellow and sinks while the other's clear and floats. I think.
There is no reaction with metallic Lead (Pb) because Pb is more stable to oxidation then Mg-metal, which is the same as saying Mg2+ ions are stable compared to Pb2+, so they are not formed from the metallic Pb
When Magnesium is added to Lead nitrate solution, it will form Magnesium nitrate and Lead.. Odd question though.
The equation:
Pb(NO3)2 + Mg à Mg(NO3)2 + Pb
Produces Sodium nitrate and a precipitate of Lead iodide
MgCl2 (aq) +2 AgNO3 (aq) -------> Mg(NO3)2 + 2 AgCl (s)
There is a white precipitate of Silver I Chloride
When aqueous solutions of these compounds are mixed together yellow precipitates of Lead iodide are formed,
Pb(NO3)2 + MgI2 -----> PbI2 + Mg(NO3)2
Lead chloride and magnesium phosphate will be formed.
yes it would
In the reaction: Lead (Ⅱ) Nitrate + Potassium Iodide → Potassium Nitrate + Lead (Ⅱ) Iodide.. all nitrates are soluble and lead(ii)iodide is insoluble.
double replacement
lead iodide crystals.. check this site out for the reaction answer.. http://en.wikipedia.org/wiki/Lead(II)_iodide
Produces yellow Lead(II) iodide and Sodium nitrate
Aqueous lead nitrate plus aqueous sodium iodide produce solid lead iodide and aqueous sodium nitrate.
In the reaction: Lead (Ⅱ) Nitrate + Potassium Iodide → Potassium Nitrate + Lead (Ⅱ) Iodide.. all nitrates are soluble and lead(ii)iodide is insoluble.
The reaction between lead(II) nitrate and sodium iodide is a double replacement reaction. The products of this reaction are lead(II) iodide and sodium nitrate, formed through the exchange of ions.
double replacement
This is a double displacement reaction. 2KI + Pb(NO3)2 --> 2KNO3 + PbI2 Potassium iodide + Lead(II) nitrate --> Potassium nitrate + Lead(II) iodide A bright yellow precipitate will form when these two react.
Lead(II) nitrate and sodium iodide will yield lead(II) iodide and sodium nitrate. This is a double displacement reaction, where the cations and anions switch partners resulting in the formation of two new compounds.
It produces Potassium nitrate and Lead iodide
lead iodide crystals.. check this site out for the reaction answer.. http://en.wikipedia.org/wiki/Lead(II)_iodide
A yellow precipitate of lead(II) iodide is formed, according to the following balanced chemical equation: Pb(NO3)2 + 2KI -> PbI2 + 2KNO3
Lead iodide is prepared from lead nitrate because lead nitrate contains lead ions and nitrate ions that can react with iodide ions to form lead iodide. This reaction allows for the precipitation of lead iodide, which can then be isolated and collected.
Produces yellow Lead(II) iodide and Sodium nitrate
Potassium iodide and lead nitrate produces lead iodide and potassium nitrate its a Precipitation Reactions. 2KI+Pb(NO3)2-->PbI2 + 2KNO3
When solutions of lead nitrate and potassium iodide are mixed, a yellow precipitate of lead iodide is formed. This reaction is a double displacement reaction where the lead from lead nitrate reacts with the iodide from potassium iodide to form the insoluble lead iodide.