Jones reagent (Dichromic acid; H2Cr2O7)
When barium sulfate is made, the limiting reagent is the one that is completely consumed in the reaction and determines the amount of product formed. In this case, if barium ions (Ba2+) and sulfate ions (SO42−) are the reactants, the limiting reagent would be the one that is present in lower molar quantity. The one in excess would be the one that is present in higher molar quantity. Without the quantities of each ion provided, it is difficult to determine which is the limiting reagent and which is in excess.
Na+ and Mg2+ can be separated by adding CO32- ions to the solution, forming MgCO3 precipitate which can be filtered off.
The reaction product of Fenton's reagent (a solution of hydrogen peroxide and ferrous iron) with silver is typically silver oxide (AgO) or silver hydroxide (AgOH) depending on the conditions of the reaction. These products are formed when the silver ions present in the solution react with the hydroxyl radicals generated by Fenton's reagent.
Using Tollens' Reagent (The Silver Mirror Test):Tollens' reagent contains the diamminesilver(I) ion, [Ag(NH3)2]+.This is made from silver(I) nitrate solution. You add a drop of sodium hydroxide solution to give a precipitate of silver(I) oxide, and then add just enough dilute ammonia solution to redissolve the precipitate.To carry out the test, you add a few drops of the aldehyde or ketone to the freshly prepared reagent, and warm gently in a hot water bath for a few minutes.Ketone : No change in the colourless solution.Aldehyde : The colourless solution produces a grey precipitate silver, or a silver mirror on the test tube.Aldehydes reduce the diamminesilver(I) ion to metallic silver. Because the solution is alkaline, the aldehyde itself is oxidised to a salt of the corresponding carboxylic acid.2Ag(NH3)2+ + RCHO + 3OH- ____} 2Ag + RCOO- + 4NH3 + 2H2OUsing Fehling's Solution or Benedict's Solution:Fehling's solution and Benedict's solution are variants of essentially the same thing. Both contain complexed copper(II) ions in an alkaline solution.Fehling's solution contains copper(II) ions complexed with tartrate ions in sodium hydroxide solution. Complexing the copper(II) ions with tartrate ions prevents precipitation of copper(II) hydroxide.Benedict's solution contains copper(II) ions complexed with citrate ions in sodium carbonate solution. Again, complexing the copper(II) ions prevents the formation of a precipitate - this time of copper(II) carbonate.Both solutions are used in the same way. A few drops of the aldehyde or ketone are added to the reagent, and the mixture is warmed gently in a hot water bath for a few minuteKetone: No change in the blue solutionAldehyde: The blue solution produces a dark red precipitate of copper(I) oxide.Aldehydes reduce the complexed copper(II) ion to copper(I) oxide. Because the solution is alkaline, the aldehyde itself is oxidised to a salt of the corresponding carboxylic acid. RCHO + NaOH +Cu(OH)2 ____} RCOONa + Cu2O + 3H2OUsing Acidified Potassium Dichromate(VI) Solution:A small amount of potassium dichromate(VI) solution is acidified with dilute sulphuric acid and a few drops of the aldehyde or ketone are added. If nothing happens in the cold, the mixture is warmed gently for a couple of minutes - for example, in a beaker of hot water. Kketone No change in the orange solution. Aldehyde Orange solution turns green.The orange dichromate(VI) ions have been reduced to green chromium(III) ions by the aldehyde. In turn the aldehyde is oxidised to the corresponding carboxylic acid.The electron-half-equation for the reduction of dichromate(VI) ions is:3RCHO + Cr2O7 -2 + 8H+ ____} 3RCOOH + 2Cr+3 + 4H2O
copper(II) ions + protein (2 or more peptide bonds) ---> biuret complex (PURPLE!) the intensity of the purple depends on how many copies of the complex have been formed.
silver nitrate (AgNO3)
When barium sulfate is made, the limiting reagent is the one that is completely consumed in the reaction and determines the amount of product formed. In this case, if barium ions (Ba2+) and sulfate ions (SO42−) are the reactants, the limiting reagent would be the one that is present in lower molar quantity. The one in excess would be the one that is present in higher molar quantity. Without the quantities of each ion provided, it is difficult to determine which is the limiting reagent and which is in excess.
what kind of bio molecule is this when mix with a benedicts reagent and biuret reagent
Ammonium ions
You're starting with something like sodium benzoate (depends on what base you used for the extraction step), which contains sodium ions (Na+) and benzoate ions (C6H5COO-). Ionic compounds like that tend to be soluble in water. When you add H+, you protonate the benzoate ion to make benzoic acid (C6H5COOH), which is a neutral molecule, and hardly soluble in water at all... so it precipitates.
You cannot. Different ions have different molecular masses.
This is due to the reduction of the cupric (Cu2+) ions in Benedict's reagent to cuprous form (Cu1+) by reducing sugars, forming cuprous oxide (Cu2O), which is a brick red precipitate. This is why Benedict's test is a good way to detect reducing sugars.
Ammonia is used as a ligand in order to dissolve the insoluble Silver ions under alkaline conditions.
Na+ and Mg2+ can be separated by adding CO32- ions to the solution, forming MgCO3 precipitate which can be filtered off.
PGAL
Millons reagent is not a compound but a mixture. It is made by dissolving mercury in nitric acid. There is a variant which Millons, Coles reagent which is a LITTLE safer as it uses sodium nitrite and sulfuric acid with mercury. The chemistry is a bit obscure- some say that it involves mercurous ions and nitrous acid. The end result is a nice red color.
A paper strip impregnated with a reagent specific for the nitrate ion; it is useful for the rapid and aproximative determination of the nitrate ions in water, soils, vegetables, etc.