That depends how they are connected. For example, if they are connected in series, just add the individual resistances.
15 ohms
400 ohms
Well, the total circuit resistance depends on the type of connection. If the two resistances (or any number of resistances) are connected in series, IE. one resistance end is connected to one end of another resistance, the the circuit total resistance is the sum of the two resistances. say two resistances r1 and r2 are connected in series the total resistance is r1+r2 (in this case its 30 ohms). If the resistances are connected in parallel IE. both the ends of a resistance are connected to both ends of another resistance then the total resistance in this case shall be (r1*r2)/(r1+r2) ,( that is 6.67 ohms in given case).
total voltage = 4.5V, total resistance = 3.5 ohms, loop current = 4.5V / 3.5 ohms = 1.286Atotal voltage = 9V, total resistance = 4 ohms, loop current = 9V / 4 ohms = 2.25Atotal voltage = 13.5V, total resistance = 4.5 ohms, loop current = 13.5V / 4.5 ohms = 3Aetc.There is no solution to your problem conditions.
Current, by Ohm's Law, is voltage divided by resistance, so, 18 volts divided by 2 ohms is 9 amperes.
15 to 40 ohms.
If they're connected in series the total resistance is 2000 ohms. If they're connected in parallel the resistance is 500 ohms.
Could it be.... 20 ohms(?)
35 ohms
400 ohms
5 ohms
5 ohms
The total resistance is 5 ohms. Scroll down to related links and look at "Parallel Resistance Calculator".
how much resistance must be connected in series with a 250 ohms inductive reactance to produce a total ciruit impedance of 400 ohms?
When a resistor is in series. Total resistance =R1+T2+R3. Therefore 20+8+4=32 The total resistance is 32 ohms.
Well, the total circuit resistance depends on the type of connection. If the two resistances (or any number of resistances) are connected in series, IE. one resistance end is connected to one end of another resistance, the the circuit total resistance is the sum of the two resistances. say two resistances r1 and r2 are connected in series the total resistance is r1+r2 (in this case its 30 ohms). If the resistances are connected in parallel IE. both the ends of a resistance are connected to both ends of another resistance then the total resistance in this case shall be (r1*r2)/(r1+r2) ,( that is 6.67 ohms in given case).
30 ohms
Three resistors in parallel: 20 ohms, 20 ohms, 10 ohms.1/ total resistance = (1/10) + (1/20) + (1/20) = (2/20) + (1/20) + (1/20) = 4/20 = 1/5 mho.Total resistance = 5 ohms