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A: Follow me on this the lm317 is a 1.25v regulator period. So to make it look like a 11.25 volts is simple assume the the regulator load is 125 ohms so the current through will be 1.25 volts divided by the 125 ohms or 10 ma. now install a resistor from the adj terminal to ground to IR drop 10v which will be added to the 1.25v so 10v divided by 10 ma =1000 ohms from adj to ground will offset the voltage by 10 plus the 1.25 volt give us 11.25 output from output to ground. since we offset the output voltage by 10 volts the adj pin only needs very little current we could have use 1250 ohms and 10k to achieve the same thing. There is a formula to calculate the output voltages but if you understand this you will have no problems. And by the way this scheme can be used for a 5 v,12v any of the three pins regulators. By changing the 1k you will change the output volts since the 1.25 volts is fixed and the 125 ohms if fixed. Furthermore to make it behave like a current source up to an amp or so all you need is a resistor in series with the load and take the output at the adj terminal and good luck.

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Q: What is the values of resistors used in the variable dc supply circuit using lm317?
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