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The element law of a capacitor in frequency domain is based on Ohm's Law, which is capacitance times voltage is equal to current. The higher frequency, the lower the capacitance and vice versa.
It can take a lot of capacitance to present a low impedance to a low frequency. Electrolytics offer lots of capacitance for a low price.
You seem to be mixing up your terminology. There is no such thing as 'self-capacitance of an inductor'! If you know the frequency and equivalent capacitance for two capacitors, then you can find the equivalent capacitive reactance of the capacitors, but that's not what you seem to be asking! I suggest you rephrase the question.
the circuit will pass waves of a lower frequency
An oscillator has a tuned circuit (inductance+capacitance) to determine the frequency. When the inductor is tapped to give the required phase-shift for oscillation it is a Hartley oscillator. When the capacitance is tapped it is a Colpitts.
Answer: Capacitance is unaffected by frequency; it does not change. Details: Capacitance is unaffected by frequency. In a capacitor, what increases with Frequency is Admittance (analogus to Conductance) . The capacitive Reactance is inversely proportional to Frequency. Therefore, when Frequency is increased, current flow may increase.
Reactance (in ohms) = 1/(2 pi * capacitance * frequency). Capacitance is in farads. Frequency is in Hertz (cycles/second). So increasing capacitance or increasing frequency will decrease reactance.
The element law of a capacitor in frequency domain is based on Ohm's Law, which is capacitance times voltage is equal to current. The higher frequency, the lower the capacitance and vice versa.
capacitive reactance is inversely proportional to the capacitance of the capacitor and frequency of the AC line reactance (in ohms) = 1/(capacitance * frequency)
It can take a lot of capacitance to present a low impedance to a low frequency. Electrolytics offer lots of capacitance for a low price.
reactance due to the capacitance of a capacitor or circuit,equal to the inverse of the product of the capacitance and the angular frequency.
Capacitive reactance Xc is equal to 1/2pi*f*C, wher f is input frequency and C is capacitance. Since for DC frequency is zero(no variation with time) Xc is infinite ideally and very very high practically.
You seem to be mixing up your terminology. There is no such thing as 'self-capacitance of an inductor'! If you know the frequency and equivalent capacitance for two capacitors, then you can find the equivalent capacitive reactance of the capacitors, but that's not what you seem to be asking! I suggest you rephrase the question.
First, capacitance is the resistance of something to a change in voltage. And capacitance exists anywhere there is a conductor that is insulated from another conductor. With that definition, anything has capacitance. And that's correct. It is also the key to understanding the capacitance in high frequency (radio frequency or RF) circuits. The fact that a circuit had conductive pathways and component leads and such means that there is a lot of little bits of capacitance distributed around the circuit. The capacitance is already there; it isn't "added" later as might be inferred. Normally, this bit of capacitance isn't a problem. But at higher and higher frequencies, it is. Remember that the higher the frequency of an AC signal, the better it goes through a given cap. So at higher and higher frequencies, the distributed capacitance in the circuit "shorts the signal to ground" and takes it out of the circuit. The RF is said to be coupled out of the circuit through the distributed capacitance in that circuit. The higher the frequency a given circuit is asked to deal with, the more signal will be lost to this effect. It's just that simple. Design considerations and proper component selection minimize the distributed capacitance in a circuit.
the circuit will pass waves of a lower frequency
An oscillator has a tuned circuit (inductance+capacitance) to determine the frequency. When the inductor is tapped to give the required phase-shift for oscillation it is a Hartley oscillator. When the capacitance is tapped it is a Colpitts.
This is a very broad generalization, but in general, increasing the value of one or more capacitors in an electronic circuit will decrease the resonant frequency of one or more sections of the circuit.