The volume is 44,828 L at 0 oC.
This volume is 6,197 399 5 at 25 0C.
The mass of 2,4 moles of chlorine is 84,08 g.
The volume of one mole of gas at a standard temperature and pressure is 22.4 liters. Multiply 22.4 liters by 0.25 moles to get a volume of 5.6 liters.
The 0.5M and 2M refer to moles per liter (of solution). Volume of final solution is 2.5 L + 500 mL = 2.5 L + 0.5 L = 3.0 L. So find out how many moles the final solution has and divide by 3.0L.First solution (0.5 moles/liter)*(2.5 liter) = 1.25 moles2nd solution (2 moles/liter)*(0.5 liter) = 1 moleMolarity: (1.25 mole + 1 mole)/(3.0 liter) = 0.75 moles/liter = 0.75 M
1 mole in 250 ml and 4 moles in 1 liter or 1000 mls
This volume is 6,197 399 5 at 25 0C.
Molarity is moles/liter, so in order to find the moles of a substance in a given volume, simply multiply molarity with volume (in liters). n=M*V
I would assume chlorine gas and standard temperature an atmospheric pressure. Using the ideal gas equation. PV = nRT (1 atm)(X volume) = (2.4 moles Cl2)(0.08206 Mol*K/L*atm)(298.15 K) Volume = 59 Liters of chlorine gas --------------------------------------------
54 liters at STP (standard temperature and pressure)
liter = unit of volume mole = unit of concentration
The volume is 254,82 L.
At STP, 1 mole of gas occupies a volume of 22.4 liters. Thus, 4/5 moles of gas will occupy .8*22.4 liters.
Molarity is defined as moles solute/liter of solution6 moles/2 liters solution = 3 molar NOTE: This assumes no volume change and 2L is the final volume of solution.
The mass of 2,4 moles of chlorine is 84,08 g.
Molarity is calculated as moles of solute divided by volume of solution in liters. In this case, you have 2 moles of sodium chloride in a 0.5 liter solution. So the molarity would be 2 moles / 0.5 L = 4 M.
There is no single standard here; sometimes, percentages are used (either volume or mass percentages; the numbers may be different for the same mixture, due to different densities); mass per volume (e.g., grams per liter); or moles per volume (e.g., moles per liter).
75,10 g of chlorine = 2,1183 moles