Br2 (g) + 2 KI (aq) 2KBr (aq) + I2 (s)
Bromine and Potassium iodide react to form Potassium bromide and Iodine.
Its actually: 2KI(aq)+Br2(aq)-> I2(s)+2KBr(aq)
2KI+Br2 ---->2KBr +I2
Unbalanced: KBr + BaI2 --> KI + BaBr2Balanced: 2KBr + BaI2 --> 2KI + BaBr2
Br2 + (2e)- --> 2 Br- 2I- --> I2 + (2e)-
Bromine and Potassium iodide react to form Potassium bromide and Iodine.
Its actually: 2KI(aq)+Br2(aq)-> I2(s)+2KBr(aq)
No. However, bromine would displace iodine in potassium iodide.
2KI+Br2 ---->2KBr +I2
2 KBr + BaI2 ----> 2 KI + BaBr2
Unbalanced: KBr + BaI2 --> KI + BaBr2Balanced: 2KBr + BaI2 --> 2KI + BaBr2
potassium
Br2 + (2e)- --> 2 Br- 2I- --> I2 + (2e)-
Yes, it can, by displacing the Iodide
Potassium bromide is KBr, so by adding together their molar masses, we get 39+80=119gmol-1
holaaa lala
Iodine and Calcium bromide