The yellow product of reaction is lead (II) iodide, PbI2. It was used as the pigment in yellow paint, just as lead (II) oxide was the pigment in white paint. However, since these compounds were linked to lead poisoning, this procedure was discontinued. Currently, lead iodide is used as a detector for high energy photons, like x-rays or gamma rays, as the lead atom is very large.
A yellow precipitate of silver iodide (AgI).
Lead iodide (Pb2I) precipitates as a yellow solid, leaving a solution of potassium and nitrate ions.
A yellow precipitate of silver iodiode (AgI) is formed.
Pb(NO3)2 + 2NaI = PbI2 = 2NaNO3 Lead iodide is a yellow precipitate.
Produces yellow Lead(II) iodide and Sodium nitrate
When potassium iodide and lead nitrate are combined, a double displacement reaction occurs, resulting in the formation of lead iodide and potassium nitrate. Lead iodide is a yellow precipitate that forms when the two solutions are mixed.
When silver nitrate reacts with potassium iodide, a precipitation reaction occurs where silver iodide is formed. The balanced chemical equation for this reaction is: AgNO3 + KI -> AgI + KNO3. The silver iodide formed will appear as a yellow solid precipitate.
When potassium iodide and lead nitrate react, lead iodide precipitate forms due to the low solubility of lead iodide in water. This reaction is a double displacement reaction where the potassium and lead ions switch partners, resulting in the formation of the insoluble lead iodide.
Lead iodide is prepared from lead nitrate because lead nitrate contains lead ions and nitrate ions that can react with iodide ions to form lead iodide. This reaction allows for the precipitation of lead iodide, which can then be isolated and collected.
A yellow precipitate of silver iodide (AgI).
This is a double displacement reaction. 2KI + Pb(NO3)2 --> 2KNO3 + PbI2 Potassium iodide + Lead(II) nitrate --> Potassium nitrate + Lead(II) iodide A bright yellow precipitate will form when these two react.
Lead iodide (Pb2I) precipitates as a yellow solid, leaving a solution of potassium and nitrate ions.
Yellow; the insoluble precipitate Lead(II) iodide is created
A yellow precipitate of silver iodiode (AgI) is formed.
Pb(NO3)2 + 2NaI = PbI2 = 2NaNO3 Lead iodide is a yellow precipitate.
The reaction of potassium iodide (KI) and lead nitrate, Pb(NO3)2 is a double displacement reaction. It looks like this: 2KI(aq) + Pb(NO3)2(aq) ==> PbI2(s) + 2KNO3(aq). Note that PbI2 is a solid, and it happens to have a yellow color.
Produces yellow Lead(II) iodide and Sodium nitrate