8,930g, or 8.93kg.
Assuming you're at standard temperature and pressure, 2000/22.4=89.3mol CO2, which means 89.3mol CaCO3. At 100g/mol, that means 8,930g CaCO3.
The chemical formula for limestone is CaCO3. When heated, limestone decomposes to produce calcium oxide (CaO) and carbon dioxide (CO2). The molar mass of CaCO3 is 100.09 g/mol. To calculate the mass of CO2 produced, you would first calculate the moles of CaCO3 in 2.00g, then use the stoichiometry from the balanced chemical equation to determine the moles and then mass of CO2 produced.
Molar mass of CaCO3 = 100.0869 g/mol
CaCO3 --> CaO + CO2 mass of CO2 = 9.8 - 4.3 = 5.5 g We assume all 9.8 g of CaCO3 decomposed.
Molar mass of CaCO3 = 66.1221g CaCO3/mole CaCO3. This means that 1 mole CaCO3 = 66.1221g CaCO3. To find the mass of 4.5 mole CaCO3, complete the following calculation: 4.5g CaCO3 X 1mol CaCO3/66.1221g CaCO3 = 0.068 mole CaCO3.
The molar mass of CaCO3 is 100.09 g/mol, and the molar mass of CO2 is 44.01 g/mol. By using stoichiometry, you can calculate that 15.2 grams of CaCO3 would produce 6.51 grams of CO2. Using the ideal gas law, you can then convert the mass of CO2 to volume using its molar volume at STP (22.4 L/mol). The volume of CO2 produced would be around 3.32 liters.
250 grams CaCO3 (1 mole CaCO3/100.09 grams) = 2.50 moles of calcium carbonate
To find the number of moles in 73.4 kg of CaCO3, we first need to calculate the molar mass of CaCO3. The molar mass of CaCO3 is 100.09 g/mol. Converting 73.4 kg to grams gives 73,400 g. Dividing 73,400 g by the molar mass of CaCO3 gives approximately 733 moles.
The molar mass of CaCO3 is approximately 100.09 g/mol. Therefore, the mass of 0.5 moles of CaCO3 would be 50.045 g.
Both C7H16 and CaCO3 have a molar mass of approximately 116 grams per mole.
No, this statement is incorrect. The molar mass of CaCO3 (calcium carbonate) is 100.09 g/mol, while the molar mass of Ca(NO3)2 (calcium nitrate) is 164.08 g/mol. Therefore, the molar mass of Ca(NO3)2 is greater than that of CaCO3.
The relative molecular mass of CaCO3 (calcium carbonate) is approximately 100.09 g/mol.
When 1 gram of calcium carbonate (CaCO3) is heated, it decomposes to produce calcium oxide (CaO) and carbon dioxide (CO2). The molar mass of CaCO3 is approximately 100 g/mol, so 1 gram corresponds to about 0.01 moles of CaCO3. According to the reaction, 1 mole of CaCO3 produces 1 mole of CO2; thus, 0.01 moles of CaCO3 will produce 0.01 moles of CO2. At standard temperature and pressure (STP), 1 mole of gas occupies 22.4 liters, so the volume of CO2 produced is approximately 0.01 moles × 22.4 L/mol = 0.224 liters, or 224 mL.