You want to get the concentration that would be in a litre. for every 750ml, there is 1 mol. so 1/750, x1000 will give you 1.333 molar. i.e. 1.333 moles in every litre.
the answer is 2.5 because it is mols of solute over liters of solution
So you dilute it 3 in 4. You have to apply this to the original molarity now. 2 molar / 4 * 3 is 1.5 molar.
Molarity = moles of solute/Liters of solution
Molarity = 2.5 moles NaOH/10 Liters
= 0.25 M NaOH
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The answer is 830,014 grams.
Molarity = Moles/Unit VolumeSo here Molarity = (0.0255) / (10-2) = 2.55 M
Molarity = moles of solute/Liters of solution Molarity = 10 moles salt/20 Liters solution = 0.50 M salt solution ----------------------------
The molarity is 0,2.
The concentration of the OH- is 8.0 x 10-4 In terms of molarity, since the hydroxide is double that of the calcium, double the molarity of the solution.
Molarity = moles of solute/Liters of solution Molarity = 5 moles sucrose/0.5 Liters = 10 M ----------
Molarity = Moles/Unit VolumeSo here Molarity = (0.0255) / (10-2) = 2.55 M
Molarity is moles per litre. So you have to convert volume to a litre. i.e. 0.5x2 is a litre. so you have to do the same to moles. 5x2 is 10 moles. as this is per litre, it is a 10 molar solution.
Molarity = moles of solute/Liters of solution 10 grams of compound ( 1mol/100g ) = 0.1 mole Molarity = 0.1 mol/1 Liter = 0.1
Molarity = moles of solute/liters of solution M = 10 mol NaOH/1 liter = 10 M -log(10 M) = -1 14 - (-1) = 15 pH sodium hydroxide
The molar mass of MgCl2 is 95.21 g. Therefore 0.96 grams is 0.01008 mol of the substance. So the molarity of the solution is 5.04 x 10-3 M.
C [mol/L] = w% * rho [g/mL] *1000 [mL/L] / (100% * M [g/mol] ) = = w% * rho [g/mL] *10 [mL/L%] / ( M [g/mol] ) = = 15.00 % * 1.04 [g/mL] *10 [mL/L%] / ( 158.034 [g/mol] ) = = 0.987 [mol/L] the molarity of the solution of potassium [in mol per liter] equals the content of KMnO4 by mass in percents multiply by density in g/mL multiply by 10 [mL/(L*%)] divide by molar mass of KMnO4 (M = 158.034 g/mol) This gives 0.987 mol/L. Thus the molarity equals approximately 1 M.
Molarity = moles of solute/Liters of solution Molarity = 10 moles salt/20 Liters solution = 0.50 M salt solution ----------------------------
Convert the 200 mol of water to kilograms of NaCl
First we need to convert grams(g) to moles(mol) and mL to L, since M(molarity)=mol/L.Ag=107.868N=14O=16 x3=48AgNO3 =169.868 g/mol42.5g x 1 mol/169.868g = .25mol AgNO3100mL x 10-3 L/ 1mL = .1LM=mol/L.25mol/.1L = 2.5M AgNO3
Is that 0.5L ? If yes, as 1L=1dm3, no. of mole= (volume)(concentration)=(0.5)(2)=1 mol
The molarity is 0,2.
The concentration of the OH- is 8.0 x 10-4 In terms of molarity, since the hydroxide is double that of the calcium, double the molarity of the solution.