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Remember the moles equations.

moles = mass(g) / Mr = [conc] x vol(mL) / 1000

Hence

mass(g) = [conc] x vol(mL) x Mr / 1000 (be algebraic rearragnement)

conc = 0.05 M

Mr = 23 + 35.5 = 58.5

vol(mL) = mass (g) = 150 g =150 mL (NB THis is the standard for water at STP)

Substituting

mas9g) = 0.05 x 58.5 x 150 / 1000

mass(g) = 0.43875 g ~ 0.44 g

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lenpollock

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8mo ago
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9y ago

The term molecule is not adequate for an ionic compound; correct is formula unit.

150 g NaCl contain the equivalent of 2,5667 formula units.

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10y ago

To prepare a 1,5 M sodium chloride solution we need 87,659 g NaCl.

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10y ago

The answer is 87,66 g NaCl.

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9y ago

The answer is 0,44 g NaCl.

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7y ago

This mass is 0,438 g.

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Q: What mass of NaCl is required to dissolve 100 g NaCl to prepare a 1.50 m solution?
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