Molar mass of NaCl =~58.4 g/mole0.1 N NaCl = 0.1 moles/liter
To make 1 liter of 0.1N NaCl thus requires 0.1 moles/liter = 0.1 moles x 58.4 g/mole = 5.84 moles
Dissolve 5.84 g (6 g using 1 sig. fig.) in a final volume of 1 liter to make 0.1N NaCl
1 percent = 10 grams 2 % = 20 grams x 3 liters = 60 grams
Weigh 22.35 grams of KCl and Dissolve in 100 mL of Distilled Water
To prepare 2L of a 5M solution, you should put in 4.6575grams of KMnO4. It is important to make sure that you add them in that order. K should be added first, then Mn.
You need 50 g of this drug.
122.5g
30 grams
40 grams, this is the 1M NaOH standard laboratory solution.
See the two Related Questions to the left for the answer.The first is how to prepare a solution starting with a solid substance (and dissolving it). The second question is how to prepare a solution by diluting another solution.
Molarity = moles of solute/Liters of solution 0.75 M KCl = moles KCl/2.25 Liters = 1.6875 moles KCl (74.55 grams/1 mole KCl) = 126 grams of KCl needed
4314.9 grams
8.9g
It depends on the final solution Volume you want to prepare. For 100ml of a 6M NaCL solution, you add 35.1g of NaCl to water until you reach 100ml. Dissolve and autoclave for 15 mins.
400 mls would require 40g of glucose for a 10% solution and thus 20g for a 5% solution.
14.575 round is 14.6 g
1% solution = 1 gram per 100 mL, 10 grams per liter 20 grams
1.17 grams :)
1 percent = 10 grams 2 % = 20 grams x 3 liters = 60 grams