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Amyl butyrate, CH3[CH2]2C(=O)-O[CH2]4CH3, IUPAC name: pentyl butanoate This ester has a smell reminiscent of pear or apricot. This chemical is used as an flavour added to cigarette- and pipe tobaccos.
CH3-C(CH3)2-CH2-X
A main component is acetone [propanon, CH3C(O)CH3 ], but sometimes butyl- and pentyl esters are also involved.
An organic alkyl radical such as methyl, ethyl, propyl, butyl, pentyl etc. 'R' is used when the reaction in which the substance is used is a generic reaction that would be the same whatever the radical.
First of all, you need to clarify your question. 4-pentylmethyl ketone, unfortunately, does not exist. You have made a mistake in the nomenclature.I am assuming that you are talking about /\/\/*\, which is the carbon skeleton of pentylmethyl ketone, with the * representing C=O. The molecular formula is C7H14O, and it is also known as 2-heptanone. I don't know why you added in the "4-", unless you mean that the methyl is coming off the fourth carbon of the pentyl group. If that is the case, and you have moved methyl off to be a substituent on the pentyl, then the compound should be named an aldehyde and not a ketone.UV spec gives you a graph with absorbance on the y-axis and wavelength (in nanometers) on the x-axis.Conjugated systems are where double bonds occur, and are separated by exactly one single bond. In other words C=C-C=C is conjugated. C=C-C-C=C is not.Conjugation reduces the energy gap between the "excited" state of electrons and the normal state. In other words, it takes less energy (and is easier) to excite electrons in compounds that have conjugated double bonds, such as 3-Methyl-2-cyclohexen-1-one. When these compounds return to their normal state, they emit a photon (light).This light can have different wavelengths, which is why molecules with conjugated double bonds are often very colorful.The energy that a photon is:E = hfSince f = c/(wavelength)E = hc/(wavelength)h is a constant, f stands for frequency, c is the speed of light, and the wavelength is measured in nanometers.High energy light has high frequency and low wavelength (to make this more intuitive: think of short and fast pulsing ultraviolet radiation from the sun...it is powerful/energetic enough to cause sunburn.)Therefore, the more conjugated bonds you have, the LESS energy it will take to excite your electrons. This means that if you have more conjugated bonds you have, the compound can give a high signal at higher the wavelength (and lower energies).Red is very low energy. This is why beta-carotene, which is basically C=C-C=C-C=C-C=C-C=C-C=C-C=C-C=C-C=C-C=C-C=C, etc is orange. That's why carrots are orange.Anyways, this is a lot of detail. Basically, it means that 3-Methyl-2-cyclohexen-1-one will give a peak in your absorbance graph, whereas you other compound probably will not (assuming that I have interpreted its incorrect name).If you see a compound, the more CONJUGATED double bonds there are, the more you will see peaks at higher wavelengths, because it takes less energy to excite the electrons in those double bonds.For example: C=C-C=C-C=C-C=C-C=C-C=C will give a signal at a higher wavelength than C=C-C=C=C=C=C=C-C=C. This is because in the second compound, there are fewer CONJUGATED double bonds (even though there are more double bonds total).Why does this phenomena happen? A double bond is between two pi-orbitals. Basically they look like 8's. One lobe comes up from the carbon atom, and one lobe goes down. The electrons float around in there. If you have a double bond, the pi-orbitals on adjacent carbons share their electrons. Now, if you look at an extended conjugated system, you can see that there is an 8 on every single carbon in line! This means that basically the "electron cloud" is dispersed over the entire molecule. Much more stable, and much less energetic (remember, high energy means not stable).Hope this helps!By the way,http://www.cem.msu.edu/~reusch/VirtualText/Spectrpy/UV-Vis/spectrum.htmmight be a good reference for you.
The Easter formed is pentyl acetate
Forms an Ester, Condensation reaction Pentyl Methanoate + Water
Amyl butyrate, CH3[CH2]2C(=O)-O[CH2]4CH3, IUPAC name: pentyl butanoate This ester has a smell reminiscent of pear or apricot. This chemical is used as an flavour added to cigarette- and pipe tobaccos.
When C4H9-Mg-Cl reacts with formaldehyde and product is treated with acidified water pentyl alcohol (1-pentanol) is formed.
If formed by esterification from pentanol and acetic acid it would be C5H11OH + CH3COOH (plus acid catalyst)------> C5H11OOCCH3 + H2O
3-Methylbutyl
CH3COOCH2CH2CH2CH2CH3
Formula: CH3COOC5H11
An amyl is a dated name in organic chemistry for pentyl.
The reactant needed to combine pentanol to produce pentyl propanoate is propanoic acid. Pentanol and propanoic acid react in the presence of an acid catalyst, such as sulfuric acid, to form water and pentyl propanoate.
Pentyl Ethanoate The structural formula looks like this: CH3-CH2-CH2-CH2-CH2-O-C(=O)* -CH3 *The double bonded O goes on top of the C and the last CH3 is attached to the C, not the double bonded O.
CH3-C(CH3)2-CH2-X