What resistance would produce a current of 120 amps from a volt battery?

What resistance would produce a current of 25 ampers?

resistance does not produce currents . you need source (like voltage source , current source ,or , discharging capacitor) to generate current .

What would the current flow be if a short circuit is put across the battery's terminals?

That will depend on the internal resistance of the battery. I = E / R Where I is the current, E is the open circuit battery voltage, and R is the internal resistance of the battery.

What is the current in a 1.5V Alkaline battery?

The current depends on what is connected to the battery's terminals. If nothing is connected to it, then there is no current, and the battery lasts quite a while. In general, the current is 1.5/resistance of the external circuit connected to the battery until that number gets too big, and then the voltage of the battery sags, because it can't deliver that much current.

What would the current be if an extra battery was added to a circuit?

If you add more batteries in series, the voltage would increase. This would drastically change the circuit. Normally this should also produce more current.The effect of adding more batteries in parallel is insignificant for many circuits. Adding more batteries in parallel is like lowering a battery's internal resistance - which, for many circuits, can be neglected.Example: The battery's internal resistance can be neglected; the battery gives a voltage of 12 volt, you connect it to a resistance of 2 ohm. According to Ohm's law, that will give you a current of 6 ampere. Note that the battery capacity does not enter the calculation! Adding a second battery (of the same kind) will produce the same voltage, thus, the same current.If you add more batteries in series, the voltage would increase. This would drastically change the circuit. Normally this should also produce more current.The effect of adding more batteries in parallel is insignificant for many circuits. Adding more batteries in parallel is like lowering a battery's internal resistance - which, for many circuits, can be neglected.Example: The battery's internal resistance can be neglected; the battery gives a voltage of 12 volt, you connect it to a resistance of 2 ohm. According to Ohm's law, that will give you a current of 6 ampere. Note that the battery capacity does not enter the calculation! Adding a second battery (of the same kind) will produce the same voltage, thus, the same current.If you add more batteries in series, the voltage would increase. This would drastically change the circuit. Normally this should also produce more current.The effect of adding more batteries in parallel is insignificant for many circuits. Adding more batteries in parallel is like lowering a battery's internal resistance - which, for many circuits, can be neglected.Example: The battery's internal resistance can be neglected; the battery gives a voltage of 12 volt, you connect it to a resistance of 2 ohm. According to Ohm's law, that will give you a current of 6 ampere. Note that the battery capacity does not enter the calculation! Adding a second battery (of the same kind) will produce the same voltage, thus, the same current.If you add more batteries in series, the voltage would increase. This would drastically change the circuit. Normally this should also produce more current.The effect of adding more batteries in parallel is insignificant for many circuits. Adding more batteries in parallel is like lowering a battery's internal resistance - which, for many circuits, can be neglected.Example: The battery's internal resistance can be neglected; the battery gives a voltage of 12 volt, you connect it to a resistance of 2 ohm. According to Ohm's law, that will give you a current of 6 ampere. Note that the battery capacity does not enter the calculation! Adding a second battery (of the same kind) will produce the same voltage, thus, the same current.

How much current and circuit that includes a 9- volt battery and a bulb with a resistance of 3 ohms?

A resistance of 3 ohms connected between the terminals of a 9-volt battery will result in a current of 3 Amperes. If the battery is one of those little ones with snaps on top, it may be able to produce 3 amperes of current for about 3 seconds before it rolls over and totally dies.

What would be the effect of increasing the voltage of the battery?

Ohm's Law states that Voltage = Resistance (Ohms) * Current (Ampere). So when you increase voltage, you increase current.

What is internal resistance of battery?

The equivalent resistance you would have to place in series with an ideal battery (which of course does not exist) of the same voltage to get the same behavior (voltage drop with load) as the real battery has. It is a mathematical modeling technique to help in circuit analysis.

What would be the result if two batteries are connected in series in terms of power and voltage and current?

If two identical batteries were connected in series, the resulting voltage would double, the available current would remain the same, and the available power would double. Note that, by Ohm's Law and the Power Law, doubling the voltage into a set resistance would double the current and quadruple the power. This is inconsistent with the battery's ability to provide a certain current, so you would also need to double the load resistance, otherwise you could damage the battery.

What is the standard amperage for c batteries?

That will depend on a few things. The current output of the battery will depend on the operating voltage of the battery and the load resistance. If you know the load resistance and operating voltage, you can calculate the current using Ohm's Law. The Ohm's Law equation is I=V/R where "I" represents current in Amps, "V" represents voltage in volts and "R" represents resistance in ohms.For a standard C battery, the operating voltage will start out at approximately 1.5 Volts but that voltage will decrease as charge is drained from the battery. The load resistance should remain constant so the current output of the battery will steadily decrease over time. You could use a multimeter to measure the voltage and load resistance across the terminals of the battery.See the related link for a Duracell C battery datasheet for more details on how a battery would operate under standard usage conditions.

What is the current when a 12 volt battery is connected through a resistance of 25 ohms?

The current flowing through the circuit can be calculated using Ohm's Law: I = V/R, where I is the current, V is the voltage (12 volts), and R is the resistance (25 ohms). Plugging in the values, the current would be 0.48 amperes.

A 9.0 volt battery connected to bulb. if a current of 0.25 Amps flows through bulb what is the resistance of bulb?

V = IR Voltage = Current * Resistance so 9 = 0.25 * R Hence R =36 Ohms

A 3.6 volt Li-ion battery is connected to a circuit that has a resistance of 2k Ω. How much current would flow?

as i=v/R then i =1.8mA