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The low slip test is used to determine the D and Q axis impedance of salient pole machines. The machine terminals are short circuited, each phase voltage and current are measured. Since the terminals are short circuited, machine voltage must be reduced to prevent excessive output currents that would damage the machine.
The junction (diode or transistor) will be destroyed.
Yes, but only at a basic level. If the diode measures low resistance in one direction, high resistance in the other, you know that it is not short-circuited. But... 1. If it's a voltage-regulator/reference (Zener) diode, you do not know whether it has the correct breakdown voltage, 2. If diode leakage is important, you have not tested for leakage and the ohmmeter test does not do this reliably, 3. Your ohmmeter test voltage is probably no more than 9 volts, so you have not tested for high-voltage breakdown, and 4. If it's a rectifier (especially a high-current diode) you have not tested its forward voltage at full load current.
In Short circuit test High Voltage side is feeded with 2-5% of the High Voltage rating to circulate approximately full load current in low voltage winding by short circuiting it. Low voltage is generally short circuited to facilitate measurements because it is more difficult to measure the quantities at high voltages.
An ideal zener diode will have zero reverse current while the reverse voltage is less than the zener voltage. Once the voltage rises above the zener voltage, the maximum reverse current will become infinite (the device will become a short). On a graph with voltage along the X axis and current along the Y axis, this would be represented by a straight vertical line crossing through the zener voltage. A practical zener diode has a monotonic change from zero current at zero volts, rising gradually as the voltage approaches the zener voltage from below, then rising sharply as the voltage is around the zener voltage. This means that with reverse voltage applied even slightly below the zener voltage there will be some current flow. This can be a problem in some circuits if not understood and accounted for.
The output short circuit current is the solar cell's current when the voltage is zero, or when it, is short circuited.
For answering this question we have to consider the constant voltage drop model of the diode which says that if voltage across diode is less then its cut in voltage than assume diode to be open circuit and if it is greater then assume diode to be short circuit.Till the input voltage is less than the cut in voltage, diode is open circuit(thus no current through the circuit). Thus entire input voltage appears across the diode as output.When input voltage is greater than or equal to cut in voltage, then short circuit the diode. Thus, there will be no voltage drop across the diode as output.Thus cut in voltage decides when to consider the diode open circuit and when short circuit. It decides when the diode will have output when it will not.
The low slip test is used to determine the D and Q axis impedance of salient pole machines. The machine terminals are short circuited, each phase voltage and current are measured. Since the terminals are short circuited, machine voltage must be reduced to prevent excessive output currents that would damage the machine.
Heat, and possibly an explosion.
The junction (diode or transistor) will be destroyed.
Yes, but only at a basic level. If the diode measures low resistance in one direction, high resistance in the other, you know that it is not short-circuited. But... 1. If it's a voltage-regulator/reference (Zener) diode, you do not know whether it has the correct breakdown voltage, 2. If diode leakage is important, you have not tested for leakage and the ohmmeter test does not do this reliably, 3. Your ohmmeter test voltage is probably no more than 9 volts, so you have not tested for high-voltage breakdown, and 4. If it's a rectifier (especially a high-current diode) you have not tested its forward voltage at full load current.
In theory it will be zero, in real life it's 0,003-0,005volts. Because the rule of ohm says: U = I * R. Shorted means that R = (almost) 0 so U will be close to zero too.
when its is short circuited there will not be any drop and hence the current will b maximum when its is short circuited there will not be any drop and hence the current will b maximum
if one diode is open circuited(a break in the circuit): it will act as a half wave rectifier .only +ve or -ve 1/2 cycles available at o/p. if one diode is short(more probable case due to burn out). this place a short across source for one half cycle,may destroy circuit.
A voltage transformer takes a primary voltage and steps it down to a smaller secondary voltage. This type of transformer will attempt to keep the secondary voltage at a specific ratio of the primary voltage. If you short it, massive current flow in the secondary is required to do this. For a similar reason a CT should never be open circuited - because it attempts to push a specific ratio of primary current through the secondary. If you open circuit the secondary, it takes a massive voltage on the secondary to accomplish this.
In Short circuit test High Voltage side is feeded with 2-5% of the High Voltage rating to circulate approximately full load current in low voltage winding by short circuiting it. Low voltage is generally short circuited to facilitate measurements because it is more difficult to measure the quantities at high voltages.
There are several ways. You can simply use a resistor to have a drop of 20v across it. You can use a diode with its negative edge connected to a 12 v supply and the positive edge as your input. When your input crosses 12 volts, the diode is turned on and causes a short circuit. If the output is also connected to the positive end of diode then it will never see a voltage above 12 volts. However, a lesser voltage is visible at the output then. This is somewhat the concept behind the clipper circuit made from diode. You can also convert this 32v dc to a digital value and then while converting it back to a 12v dc through DAC (here your DAC should ideally give a constant dc output).