Since the 8085 has a maximum clock frequency of 6 MHz, increasing the crystal frequency from 5 MHz to 20 MHz, a corresponding clock frequency change of 2.5 MHz to 10 MHz, the chip would malfunction.
The crystal frquency in an 8085 system is twice the desired clock frequency, so a crystal of 2.2 MHz is required to operate at 1.1 MHz.Note: Clock frequency is not the same as instructions per second, because the instructions in an 8085 take a variable number of clock cycles, between 4 and 18, to execute.
with neat diagram explain the system bus structure of 8085
Vss, also known as Gnd, is pin 20 on the 8085.
At a clock frequency of 5 MHz (10 MHz crystal) the 8085 has a clock period of 200 ns. An instruction using 18 cycles would use 3.6 us. (Microseconds)This is for the case with no wait states. Each wait state adds 200 ns. Since an 18 cycle instruction has 5 memory accesses, one wait state per access would add 1 us to the execution time.
HL is a register pair that is used to store 16-bit data in 8085 Microprocessor
The clock out frequency of an 8085 is one half the crystal frequency. The period of one T cycle is the inverse of the clock frequency. At a crystal frequency of 5MHz, the clock is 2.5MHz, and T is 400 ns.
The crystal frquency in an 8085 system is twice the desired clock frequency, so a crystal of 2.2 MHz is required to operate at 1.1 MHz.Note: Clock frequency is not the same as instructions per second, because the instructions in an 8085 take a variable number of clock cycles, between 4 and 18, to execute.
There is no 8085 that operates at 101 MHz. The fastest 8085 operates at 12 MHz, requiring a 24 MHz crystal.
The duration of one T-state is one divided by the clock frequency, or two divided by the crystal frequency. This is for the 8085.
At a crystal frequency of 6MHz, the 8085 microprocessor has a clock frequency of 3MHz, or a period of 333 nanoseconds. The NOP instruction requires four clock cycles, three to fetch and one to execute, so the NOP instruction with a crystal frequency of 6MHz would take 1.333 microseconds to fetch and execute. This does not include wait states, each of which would add 0.333 microseconds to the timing.
crystal is a oscilltor in microprocessor
The crystal oscillator frequency in the Intel 8085 is divided by 2 because Intel designed it that way. Internal actions in the 8085 occur at various points in the cycle and, by dividing by 2, Intel could create 4 distinct points in the cycle where various edges could perform actions.
The clock speed of the 8085 depends on the particular chip chosen. The basic 8085 could run up to around 3 MHz. The -1 version could run up to around 6 MHz. The -2 version could run up to around 5 MHz. In each case, the crystal frequency had to be exactly twice the desired clock frequency, i.e. 6 Mhz, 12 MHz, and 10 MHz, respectively. In all cases, the minimum clock frequency was 500 KHz. (Crystal 1 MHz)
The operating frequency of 8085 is 3 mhz to 5 mhz
From the Wikipedia article, it looks like they would operate at 3, 5, or 6 megahertz (MHz), or maybe it's 3.5 MHz and 6 MHz (they use 3,5 - not sure if that's a European decimal point or a comma)
Internally two crystal oscillator cycles are used as one single cycle. During one single crystal cycle it is made to logic high and logic low in next cycle so, that 50% duty cycle is maintained.
The CLK signal in the 8085 is the system clock, which is the External Input Frequency or Crystal divided by two. It can be used to develop bus control logic, because it is essentially the inverse of ALE for one half clock cycle.