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Q: What would you need to do to calculate the molality of 10 h of NaCl in 2 kg of water?
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What is the molality of a solution composed of 20.2 g NaCl dissolved in 685 g of water?

The answer is 0,505.


What is is the molality of 3.00 of NaCL and 1.50kg?

m = moles/kg = 3.00/1.50 = 2.00 molal


What would you need to calculate the mole of ten g of NaCl in 2 Kg of water?

You need to know the molar mass of NaCl. Then 10g/molar mass = moles.


What would you needto do to calculate the molality to 10 molecules of NaCl in 200 molecules of water?

Molality of a solution is defined as the number of gram moles, for molecular compounds, or gram formula unit masses, for ionic compounds, mixed with each kilogram of solvent. Sodium chloride is the solute in the question, and water is the solvent. Avogadro's Number is defined as the number of formula units required to constitute one gram formula unit and has the value of about 6.022 X 1023. Therefore, 10 formula units of NaCl constitutes 10/(6.022 X 1023) or about 1.6606 X 10-23 gram formula unit. The gram molecular mass of water is 18.0518. Therefore, 200 molecules of water contains (200)(18.0518)/(6.022 X 1023) or about 599.5 X 10-23 grams or 0.5995 X 10-23) kilograms. Therefore, the molality of the given mixture is 1.6606/0.59995* or about 2.768. ________ *The number 10-23 appears in both numerator and denominator, and therefore need not be included in this fraction.


What is Percent Concentration?

Percent concentration could mean many things...MOLARITY is defined as the moles of solute per unit volume of solution so 5 moles of NaCl in one liter of solution would be 5M (molar) NaCl solution.(Note: Solution is the solvent and solute combined, usually the solid is added and then the solution is filled to a certain line once the solid has dissolved.)MOLALITY is defined as the moles of solute per kilogram of solvent (NOT solution). So 5 moles of NaCl in one kilogram of water makes 5 mol/kg NaCl. (sometimes the symbol m is used for molality but is often confused with the unit of meters).For other types of "percent concentration" of solutions check:http://en.wikipedia.org/wiki/ConcentrationA cursory glance seemed to confirm the accuracy of the information.

Related questions

What would you need to do to calculate the molality of 10 mol of NaCl in 200 mols of water?

Convert the 200 mol of water to kilograms of water.


What would you need to do to calculate the molality of 10 mol NaCl in 200 mol of water?

Convert the 200 mol of water to kilograms of water.


What would you need to do to calculate the molality of 10 g of NaCl in 2kg of water?

58,49 g NaCl---------------------1 N10 g---------------------------------xx= 10/58,49=0,171 N58,49 is the molar mass of NaCl (for the foemula unit).Molality= 0,171/2=0,085


What would you need to do to calculate the molality of 10 g of NaCl in 2kg water?

58,49 g NaCl---------------------1 N10 g---------------------------------xx= 10/58,49=0,171 N58,49 is the molar mass of NaCl (for the foemula unit).Molality= 0,171/2=0,085


What would you need to do to calculate the molality of 10 mol of NaCl in 200 mol of water?

Convert the 200 mol of water to kilograms of water.


A solution of nacl and water has a molality of 4.5m?

The concentration of NaCl is 263 g/L


What would you need to do to calculate the molality of 0.2 kilogram of NaCl in 3 kilogram of water?

convert the .2 kg of NaCl to moles of NaCl.


What is the molality of a solution that has 70g of NaCl dissolved in 300g of water?

Molality(m)= moles of solute divided by kilograms(kg) of solvent you need to find the moles of NaCl by using a conversion factor 70g NaCl = 1mol divided by 58.44g NaCl =1.20mol then you need to convert 300g of water which is the solvent to kilograms by moving the decimal over 3 units to the left which makes .300 kg of solvent Molality= 1.20mol divided by .300kg Molality=4.00


The density of 3 M solution of NaCl is 1.25 g mL-1 Calculate the molality of the solution?

2.79


What is the molality of .630g of NaCl dissolved in 525g of water?

0.630 g NaCl x (1 mol NaCl/58.44 g NaCl) = 0.0108 mol NaCl525 g H2O x (1 kg/1000g) = 0.525 kg H2O0.0108 mol NaCl/0.525 kg H2O = 0.0206 molality


What is the molality of a solution composed of 20.2 g NaCl dissolved in 685 g of water?

The answer is 0,505.


What is the molality of a solution in which 3.0 moles of NaCl is dissolved in 1.5 Kg of water?

2mol/kg