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The ionic equation for the reaction is OH- + H+ -> H2O.

Since potassium is monovalent, the solution of potassium hydroxide will contain the same number of gram formula masses of hydroxide ions as the number of moles of the salt. The total number of gram formula masses of hydroxide available for reaction from the stated quantity of KOH solution is (25.00/1000)0.250 or 6.25 X 10-3.

Sulfuric acid is divalent, so that there are two gram formula masses of H+ per mole of sulfuric acid. The total number of gram formula masses of hydrogen cations contained in the specified amount of sulfuric acid solution .is therefore 2(20.00/1000)0.5 or 20.00 X 10-3.

Potassium hydroxide is therefore the limiting reagent, and the number of moles of water produced will be 6.25 X 10-3.

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Q: When 25.00 ml of 0.250 M potassium hydroxide solution reacts with 20.00 ml of 0.500 M sulfuric acid solution how many moles of water will be produced?
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What is the name and formula of the salt produced in the neutralization of sulfuric acid by potassium hydroxide?

Potassium sulfate = K2SO4


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