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by adding resistance in parallel more current is bound to flow
Adding more lamps in parallel (across) a line will cause total current to climb. It will keep climbing (increasing) until a load protection device (circuit breaker or fuse) breaks the circuit or until something fails because of excessive current.
V=IRyou are adding in parallel, so V is non-zero, because R is positive, I must have the same sign as V. Therefore your current will increase.
This is a very technical electrical question that may be difficult to understand without further study. But adding appliances to an outlet is the same as adding resistance in parallel. Adding resistance in parallel, the resistance of the circuit goes down. That is why you get more current flow. By contrast, adding resistance in series increases the resistance of the circuit and therefore reduces current, all else being equal.
Adding more loads in a parallel circuit increases the current because of Kirchoff's voltage and current laws, and because of Ohm's law...1. Kirchoff's voltage law states that the signed sum of the voltage drops around a series circuit is zero. A consequence of this is that the voltages across elements of a parallel circuit must be the same.2. Ohm's law states that current is voltage divided by resistance. Since the voltage across each new parallel element is the same, the current in that element is known. A consequence of this is that each additional element does not change the current in the other elements.3. Kirchoff's current law states that the signed sum of the currents entering a node is zero. A consequence of this, and 1 and 2 above, is that the currents added by each parallel element increases the total current entering the set of parallel elements.
by adding resistance in parallel more current is bound to flow
Adding more lamps in parallel (across) a line will cause total current to climb. It will keep climbing (increasing) until a load protection device (circuit breaker or fuse) breaks the circuit or until something fails because of excessive current.
V=IRyou are adding in parallel, so V is non-zero, because R is positive, I must have the same sign as V. Therefore your current will increase.
The current (amps) will remain constant, but the voltage will drop.
The total resistance of a set of resistors in parallel is found by adding up the reciprocals of the resistance values, and then taking the reciprocal of the total. By removing a resistor the total current will lower. If you short out the parallel circuit as suggested it will take out the fuse that should be protecting the circuit.AnswerShorting-out a resistor in a parallel circuit, will act to short out the entire circuit, therefore, significantly increasing, not lowering, the current! And, as the previous answer indicates, this short-circuit current will operate any protective devices, such as a fuse.In a parallel circuit current does not lower but it will be increase if shorting-out one resistor in the two resistor parallel circuit, the circuit will become very low resistive and the larger current will flow through the short path.
no
This is a very technical electrical question that may be difficult to understand without further study. But adding appliances to an outlet is the same as adding resistance in parallel. Adding resistance in parallel, the resistance of the circuit goes down. That is why you get more current flow. By contrast, adding resistance in series increases the resistance of the circuit and therefore reduces current, all else being equal.
Adding more loads in a parallel circuit increases the current because of Kirchoff's voltage and current laws, and because of Ohm's law...1. Kirchoff's voltage law states that the signed sum of the voltage drops around a series circuit is zero. A consequence of this is that the voltages across elements of a parallel circuit must be the same.2. Ohm's law states that current is voltage divided by resistance. Since the voltage across each new parallel element is the same, the current in that element is known. A consequence of this is that each additional element does not change the current in the other elements.3. Kirchoff's current law states that the signed sum of the currents entering a node is zero. A consequence of this, and 1 and 2 above, is that the currents added by each parallel element increases the total current entering the set of parallel elements.
In the case of an a.c. circuit, capacitors oppose current because of their capactive reactance, expressed in ohms. Capacitive reactance is inversely-proportional to the capacitance of the capactor and to the frequency of the supply. So, adding a capacitor is series with an existing load will reduce the load current. On the other hand, adding a capacitor in parallel with an existing load will decrease the load current.
Current can be increased by adding a larger load to the circuit.
Do nothing. But in a parallel circuit, all the bulbs will get dimmer.
When you add a light bulb, you are adding a load, which performs a function - in this case, it converts electrical energy to light and heat energy. When you add an ammeter, most of the time you intend to measure the current in the circuit, which is the function of the ammeter. Thus the two electrical components differ in their function and does different things when added to a circuit.