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Which genotype will make their child have freckles?
Bullseye: *Whistles* Ha ha ha! Daredevil: That's him... That's your father's... Don't... Elektra: He has to pay for what he's done. Daredevil: I don't want to lose you again. Bullseye: Ha ha ha! Come on, girl! Elektra: I'll find you. Bullseye: *Whistles at Elektra* Ha Ha Ha! Hey orphan, let's play!
What is the probability of a child having cystic fibrosis if one of her parents was homozygous dominant and the other was a carrier for cystic fibrosis?
Assuming that each parent is a carrier for cystic fibrosis (has the genotype Ff), the probability that their second child will develop cystic fibrosis is one fourth. The probability doesn't change with the number of children they have. For each pregnancy, the chance that the child will have cystic fibrosis (have the genotype ff) is exactly the same.
Is Ff heterozygous?
which of mikes traits are heterozygous? Gg or ee or CC or Ff
If the dominant allele F produces yellow flower color and re recessive allele f produces white flower color what are the possible pairs of alleles that would produce the yellow-flower phenotype?
FF, fF, Ff
If feather color in parrots is made by 1 autosomal gene with 2 alleles F and f The F is blue and f is yellow F allele shows imcomplete dominance over f allele 2 heterozygous Ff green parrots bred?
First, to restate the question in a more comprehensible form:Feather colour in parrots is determined by a single autosomal gene. The gene has two alleles, F and f. F causes blue feather colour and f causes yellow feather colour. F shows incomplete dominance over f (i.e, a heterozygote has a mixed phenotype, green feathers). If two green parrots, genotype Ff breed, what colour will the offspring be?This is a basic Mendelian cross. A similar example, with Punnet square, can be seen in the Wikipedia page for 'Mendelian inheritance', Figure 3. This page is a good starting point for understanding the principles involved.To directly answer the question, 25% of the offspring will be blue (FF), 25% yellow (ff) and 50% green (Ff).
What genotype is ff?
recessive
What is the child's genotype if parents both have normal arches produce a child with flat feet?
Child's genotype would be homozygous recessive alleles (nn) and parents would both have heterozygous dominant alleles (Nn).
What is genotype hybrids?
Mm, Ff, Gg, Ll, Ss and ect
What is a hybrid genotype?
Mm, Ff, Gg, Ll, Ss and ect
Having freckles is dominant (F), and not having freckles is recessive (f). A mother has Ff and a father has ff. If they have a child, which genotype will make their child not have freckles?
ff (apex)
Having freckles is dominant (F) and not having freckles is recessive (f). A mother has Ff and a father has ff. If they have a child which genotype will make their child not have freckles?
ff (apex)
What are the genotypes of offspring from an FF X ff cross?
The offspring from an FF X ff cross will all have the genotype Ff.This is because they receive one allele from each parent, and in this case they can only receive an F from the FF parent and an f from the ff parent.
An AABbccDdEeFF individual is crossed with an individual with the genotype AaBBCCDdEeff what is the probability that their offspring will have the genotype AaBBCcddEEFf?
Cross each allele separately to get the final genotype: AA x Aa = AA, aa, Aa, Aa .: 1/2 Bb x BB = BB, BB, Bb, Bb .: 1/2 cc x CC = Cc .: 1 Dd x dd = DD, dd, Dd, Dd .: 1/2 Ee x Ee = EE, Ee, Ee, ee .: 1/4 FF x ff = Ff, Ff, Ff, Ff .: 1 Multiply all probable fractions: 1/2 x 1/2 x 1 x 1/2 x 1/4 x 1 = 1/64 chance of that specific genotype.
Freckles are a dominant characteristic The appearance of freckles is the phenotype what represents a heterozygous genotype for freckles?
If all of the children have freckles, that means that both parents had dominant genotypes. (Mother; FF and Father; FF). Or, one parent could have a hybrid genotype. (For example, Mother; Ff and Father; FF). Based on the outcome of a Punnett Square, either one parent must have a hybrid and the other dominant, or both must have dominant genotypes.
What is the broadcast MAC address in hexadecimal notation?
FF-FF-FF-FF-FF-FF
If dad has freckles and is homozygous and mom has freckles and is heterozygous what phenotypes and genotypes can you expect their offspring?
Alright, I suppose I will do your homework for you.. Here is your punnet square: F F F FF FF f Ff ff Therefore, 3/4, or 75%, offspring will have the phenotype of having freckles, and 1/4, or 25% will have the phenotype of no freckles. And 2/4, or 50%, of the offspring will have the genotype for homozygous for freckles, 1/4, or 25%, of the offspring will carry a heterozygous trait for freckles, and 1/4, or 25%, of the offspring will have the phenotype for homozygous no freckles.
What phenotype will the offspring have if the punnett square is FF Ff FF Ff?
all dominant
