Want this question answered?
If the wire length is 100m and the Diameter is 1mm calculate the Resistance of wire?
In series like so ---6 ohms ---- 12 ohms --- , the total resistance is just 6 ohms + 12 ohms.assuming you mean in parallel like this:_|---6 ohms-----|-|~|-_|---12 ohms---|then the resistance of this can be calculated like so:1/6 ohms + 1/12 ohms = 1/R (where R is the resistance of the circuit as a whole)2/12 ohms + 1/12 ohms = 1/R3/12 ohms = 1/R1/4 ohms = 1/Rso R = 4 ohmsA few notes, if the resistors are in parallel the total resistance will always be less than or equal to the lowest resistance in parallel (i.e 6 ohms in parallel with 12 ohms will have resistance less than 6 ohms).Also if two resistances in parallel are the same, then the resistance is half of the resistance of both resistors (i.e. 1/2 ohms + 1/2 ohms = 1/R; 1 = 1/R, R=1 ohm which is half of 2 ohms).This process can be extended to 2 or more resistors in parallel.i.e if we had a 6 ohm, 6 ohm and 12 ohm resistor in parallel we could go1/6 ohms + 1/6 ohms + 1/12 ohms = 1/R(1/6 ohms + 1/6 ohms) + 1/12 ohms = 1/R1/3 ohms + 1/12 ohms = 1/R4/12ohms + 1/12 ohms = 1/R5/12 ohms = 1/Rso R = 12/5 ohms or 2.4 ohms
we have this 1/Re = (1/R1)+(1/R2) for calculating the effective resistance when resistances are connected in parallel so the answer would be Re =( 70*30) / (70+ 30) = 21 ohms
The combined resistance will be 2 Ohms.
10.2 kilo ohms is the resistance necessary for 1 volt to induce a current of 98.04 micro amperes. Ohm's law: voltage equals current times resistance.
Its resistance would be half , 0.5 ohms is the answer.
If the wire length is 100m and the Diameter is 1mm calculate the Resistance of wire?
Lets say the resistance of copper wire is 1 ohm per meter and the wire is 10 meters long then resistance of wire is 10 ohms* If we then theoretically take the resistance of the wire at 10 ohm* and the voltage from the source at 10V then the current would be* I=V/R 10/10 or 1A If we shorten the wire to 9m then resistance of wire is 9 ohms so current if V does not change would be I=V/R 10/9 or 1.111111111111111111111A *This is without loss or other factors
Trick question. From Ohms law resistance equals voltage over current (R=V/A). To get 1 ampere at 1 volt the resistance must be 1 ohm!
In series like so ---6 ohms ---- 12 ohms --- , the total resistance is just 6 ohms + 12 ohms.assuming you mean in parallel like this:_|---6 ohms-----|-|~|-_|---12 ohms---|then the resistance of this can be calculated like so:1/6 ohms + 1/12 ohms = 1/R (where R is the resistance of the circuit as a whole)2/12 ohms + 1/12 ohms = 1/R3/12 ohms = 1/R1/4 ohms = 1/Rso R = 4 ohmsA few notes, if the resistors are in parallel the total resistance will always be less than or equal to the lowest resistance in parallel (i.e 6 ohms in parallel with 12 ohms will have resistance less than 6 ohms).Also if two resistances in parallel are the same, then the resistance is half of the resistance of both resistors (i.e. 1/2 ohms + 1/2 ohms = 1/R; 1 = 1/R, R=1 ohm which is half of 2 ohms).This process can be extended to 2 or more resistors in parallel.i.e if we had a 6 ohm, 6 ohm and 12 ohm resistor in parallel we could go1/6 ohms + 1/6 ohms + 1/12 ohms = 1/R(1/6 ohms + 1/6 ohms) + 1/12 ohms = 1/R1/3 ohms + 1/12 ohms = 1/R4/12ohms + 1/12 ohms = 1/R5/12 ohms = 1/Rso R = 12/5 ohms or 2.4 ohms
Three resistors in parallel: 20 ohms, 20 ohms, 10 ohms.1/ total resistance = (1/10) + (1/20) + (1/20) = (2/20) + (1/20) + (1/20) = 4/20 = 1/5 mho.Total resistance = 5 ohms
Assuming the allowed volt drop is 5% or 5.5 volts, the wire resistance has to be 5.5/15 ohms or less, 0.367 ohms. The total length of wire is 600 metres so the resistance per metre is 0.00061 ohms. 1 sq-mm copper wire has a resistance of 0.0168 ohms/metre so you need wire with a size of 0.0168/0.00061 sq-mm, or 27.5 sq-mm. The next size up is 35 sq-mm in European cable size, or #2 AWG in America.
The voltage drop must be less than 5%, which is 11 volts. Thus the total resistance must equal 11/50 ohms or less, that is 11 volts divided by 50 amps. For a two-wire line the total wire length is 700 feet so the required resistance per foot is 11/(50*700) ohms per foot, or 0.000314 ohms per foot, equal to 0.001 ohms per metre for a single wire. A wire of 1 sq. mm. cross section has a resistance of 0.0168 ohms per metre, we need .001 ohms per metre, therefore the wire needs a cross section of more than 16.8 mm sq. In the USA that means the necessary wire size is 5 AWG.
The total resistance is 5 ohms. Scroll down to related links and look at "Parallel Resistance Calculator".
Power = 1 A and resistance = 1100 Ohms.
R = 1/[1/2 + 1/4 + 1/6 + 1/10] Add up the reciprocals of the resistances, and take the reciprocal of the answer.
the answer is ohms