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One electron is transferred from each sodium to each chloride.
Chlorine will gain one electron when forming an ion. Chlorine therefore fills its valence electron shell with 8 e-. Chlorine usually bonds with group 1 metals, like Na (Sodium).
Octet configuration refers to how elements generally prefer to form bonds so as to attain an octet configuration, i.e. have 8 electrons in their valence shell. For example, chlorine (Cl) is from Group VII and has 7 valence electrons. It will gain one electron (eg from sodium which loses one electron to form Na+) to form Cl-, which has 8 valence electrons and so fulfills the octet rule and is stable. The electronic configuration of sodium is 2.8.1 (if you're in secondary school), or 1s2,2s2,2p6,3s1 (more advanced). So by losing one electron to form Na+, sodium also attains octet configuration.
When solid sodium chloride is placed in water, water molecules form bonds to the sodium and chlorine ions. Since these bonds are quite strong compared to the ionic bonds, the sodium and chlorine are pulled apart. The result is sodium and chlorine atoms surrounded by a hydration shell (group of water molecules).
Hydrogen and helium have different valence electron configurations. Hydrogen has one valence electron, and helium has two valence electrons. However, hydrogen does typically form covalent bonds in which it shares an electron, and thereby gains an effective electron configuration of two, like helium. Hydrogen also can form the H+ ion which has no electrons.
The electron is transferred to chlorine.
two chlorine atoms
A chlorine atom can form ionic bonds by accepting an electron and covalent bonds by sharing electrons.
Chemical bonds are formed by sharing of electrons between two atoms. Atoms tend to achieve electronic configuration of their respective inert gases i.e. in the outer shell they need to have 8 electrons. e.g. Sodium has 1 electron in the outer shell by donating it it is left with electronic configuration of 2, 8. and Chlorine which has 7 electrons in its outer shell receives 1 electron and gets electronic configuration 2,8,8. Between Sodium and Chlorine ionic bond is formed and NaCl is produced. Chemical bonds are formed by sharing of electrons between two atoms. Atoms tend to achieve electronic configuration of their respective inert gases i.e. in the outer shell they need to have 8 electrons. e.g. Sodium has 1 electron in the outer shell by donating it it is left with electronic configuration of 2, 8. and Chlorine which has 7 electrons in its outer shell receives 1 electron and gets electronic configuration 2,8,8. Between Sodium and Chlorine ionic bond is formed and NaCl is produced.
it is an ionic bond. The sodium donates its one valence electron to Chlorine and results in ionic bond
One electron is transferred from each sodium to each chloride.
The sodium atom gives an electron to the chlorine atom to make the sodium and chloride ions respectively. Then they form ionic bonds forming sodium chloride.
Sodium chloride has ionic bonds.
Metals lose electrons to the non-metals, which gain electrons, in order to achieve a noble gas configuration, and therefore become stable. Take for example, sodium and chlorine. A sodium atom will lose one electron to a chlorine atom, and become an ion with a 1+ charge. This causes the sodium ion to have the electron configuration of the noble gas neon. The chlorine atom becomes an ion with a 1- charge. This causes the chloride ion to have the noble gas configuration of argon. The oppositely charged ions form an electrostatic attraction between them called an ionic bond.
Chlorine will gain one electron when forming an ion. Chlorine therefore fills its valence electron shell with 8 e-. Chlorine usually bonds with group 1 metals, like Na (Sodium).
Octet configuration refers to how elements generally prefer to form bonds so as to attain an octet configuration, i.e. have 8 electrons in their valence shell. For example, chlorine (Cl) is from Group VII and has 7 valence electrons. It will gain one electron (eg from sodium which loses one electron to form Na+) to form Cl-, which has 8 valence electrons and so fulfills the octet rule and is stable. The electronic configuration of sodium is 2.8.1 (if you're in secondary school), or 1s2,2s2,2p6,3s1 (more advanced). So by losing one electron to form Na+, sodium also attains octet configuration.
Ions are formed by either adding or removing an electron from elements. Ions are typically formed for stability purposes. For example, Sodium(Na), has a valence shell of 3s1, meaning that it only has one electron in its valence shell. The most stable valence configuration for an atom is one in which it has 8 electrons in its valence shell(also known as a noble gas configuration). Because of this, sodium will readily give up an electron to obtain it's noble gas configuration, which is that of Neon(Ne). These ions are typically formed from ionic bonds, where a metal and a non-metal will bond and transfer electrons. When sodium bonds to chlorine, sodium gives up an electron to chlorine to achieve a stable state. Chlorine will readily accept the electron because it only needs one more electron to fill its valence shell. Consequentially, sodium chloride(NaCl), or regular salt, will form an ionic solution when dissolved in water. Hope this helps.