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KClO3+3H2SO3=KCl+3H2SO4
kclo3
There is no such thing as KCIO3. That should be a lowercase L, not an I. (all two-letter element symbols use a lowercase for the second letter) That being said, KClO3 is Potassium Chlorate. K = Potassium Cl = Chlorine O = Oxygen 3 = number of Oxygen atoms in the molecule
Potassium chlorate (KClO3) has 3 oxygen atoms.
2KClO3(s)+MnO2(s) → 2KCL(s)+3O2(g)
The chemical formula (not equation) is KClO3
O2 is oxygen molecule; KCl is potassium chloride
The actual formula is KClO3 (with a lowercase L) Balanced equation: 2KClO3 --> 2KCl + 3O2
KClO3
This reaction is:2 KClO3 = 3 O2 + 2 KCl
Unbalanced Equation: KClO3 ===> KCl + O2 Balanced Equation: 2KClO3 ===> 2KCl + 3O2
You're asking if this is balanced: KClO3 → KCl + O2 Count up each atom of each element and make sure they're equal. On the left side, you have three oxygens. On the right, there are two. So no, this isn't quite balanced. The balanced equation is: KClO3 → KCl + (3/2) O2 Now you have three oxygens on the left side and 3/2 × 2 = 3 oxygens on the right. This is fine, but you might want a whole number mole ratio, in which case you multiply each term by 2. 2 KClO3 → 2 KCl + 3O2
KClO3 --> KCl + 3O2 is a decomposision or breakdown reaction or reversed oxidation
2 to 3, because of the balanced equation:2 KClO3 --> 2 KCl + 3 O2
2 grams of Oxygen can be obtained from 5 grams of KClO3 (only if the "CL" means "Cl", which is Chlorine! Remember that only the first letter of the atomic symbol is capitalized.)
2KClO3 --> 2KCl + 3O2
2KClO3==>2KCl+3O2 is the equation. so you need 4 moles of KClO3.