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Which has a greater number of atoms 3 grams of iron or 2 grams of sulfur?
Wiki User
∙ 7y ago
In order to compare the number of atoms, one needs to first convert the masses into moles:
3 g Fe x 1 mole/55.8 g = 0.054 moles Fe
2 g S x 1 mole/32 g = 0.063 moles S
Therefore, 2 g of sulfur contains more atoms than does 3 g of Fe. This is because 1 mole of ANY element contains 602x10^23 atoms, so the more moles you have, the more atoms you have.
Wiki User
∙ 7y ago
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How many atoms are in 25.1 grams in sulfur?
25,1 grams sulfur contain 4,7147765.10e23 atoms.
How many atoms are 6.02 grams of sulfur?
6.02 grams sulfur (1mole S/32.07 grams)(6.022 X 10^23/1 mole S) = 1.13 X 10^23 atoms sulfur
How many atoms of sulfer are present in 155 grams of sulfer?
The atomic weight of sulfur is about 32.066. Therefore, 155 grams of sulfur contains 155/32.066 or about 4.83 gram atomic masses of sulfur to the justified number of significant digits. Each such gram atomic mass contains Avogadro's number of atoms, for a total of 4.83 X 6.022 X 1023 or 2.91 X 1024 atoms.
How many atoms of sulfur are in a 48.0 g chunk of sulfur?
48.0 grams sulfur (1 mole S/32.07 grams)(6.022 X 10^23/1 mole S) = 9.01 X 10^23 atoms of sulfur
How many moles of atoms are there in 48.096 grams of sulfur?
Full formal set up. 48.096 grams sulfur (1 mole S/32.07 grams)(6.022 X 1023/1 mole S)(1 mole S atoms/6.022 X 1023) = 1.4997 moles of sulfur atoms ---------------------------------------
How many atoms are in 25.1 grams in sulfur?
25,1 grams sulfur contain 4,7147765.10e23 atoms.
What is the of 3.09x10 24 atoms of sulfur in grams?
3,09x10e24 atoms of sulfur in grams is equal to 164,65 g.
How many ATOMS of sulfur are present in 9.96 grams of sulfur trioxide?
The formula for sulfur trioxide is SO3. The molecular weight is 80.06. The atomic weight of sulfur is 32.06. Therefore, the fraction by weight of sulfur in sulfur trioxide is 32.06/80.06 is 0.4004, to the justified number of significant digits, so that 9.96 grams of sulfur trioxide contains 3.988 grams of sulfur. The number of atoms present in 3.988 grams of sulfur therefore is Avogadro's Number X (3.988/80.06) or 3.000 X 1021 atoms, to the justified number of significant digits. (Note: A depressed final digit in a decimal means that the digit may not be significant.)
How many sulfur atoms are in 3 grams of sulfur?
1.12875 × 1023
How many atoms of sulfur are present in 155 g of sulfur?
93,341,000,000,000,000,000,000,000 or 933.41 x 1023 atoms of arsenic. You just take Avogadro's number (6.022 x 1023) and multiply 6.022 by the number of moles (155) and then multiply the product by 1023.
How many atoms are 6.02 grams of sulfur?
6.02 grams sulfur (1mole S/32.07 grams)(6.022 X 10^23/1 mole S) = 1.13 X 10^23 atoms sulfur
How many atoms does g of sulfur contain?
Just about 6.022 X 1023 atoms of sulfur. Sulfur is 32.07 grams per mole.
What is the mass of 3.09X1024 atoms of sulfur in grams?
I think you meant 3.09x10^24 atoms of sulfur. 3.09x10^24 atoms * (1 mol / 6.02x10^32 atoms) * (32 g / 1mol) = 165 grams
How many atoms does 32 g sulfur contain?
Just about 6.022 X 1023 atoms of sulfur. Sulfur is 32.07 grams per mole.
How many atoms 32 g of sulfur contain?
Just about 6.022 X 1023 atoms of sulfur. Sulfur is 32.07 grams per mole.
How many atoms of sulfer are present in 155 grams of sulfer?
The atomic weight of sulfur is about 32.066. Therefore, 155 grams of sulfur contains 155/32.066 or about 4.83 gram atomic masses of sulfur to the justified number of significant digits. Each such gram atomic mass contains Avogadro's number of atoms, for a total of 4.83 X 6.022 X 1023 or 2.91 X 1024 atoms.
What is the molar mass of sulfur molecule?
A sulfur molecule has the formula S8. Multiply the number of sulfur atoms (8) times the atomic weight of sulfur in grams (32.065g). The molar mass of S8 = 256.52g S8.
